Input interpretation
nitric acid + lead(II, IV) oxide ⟶ water + lead(II) nitrate + lead dioxide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and Pb: H: | c_1 = 2 c_3 N: | c_1 = 2 c_4 O: | 3 c_1 + 4 c_2 = c_3 + 6 c_4 + 2 c_5 Pb: | 3 c_2 = c_4 + c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 2 c_4 = 2 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + ⟶ 2 + 2 +
Structures
+ ⟶ + +
Names
nitric acid + lead(II, IV) oxide ⟶ water + lead(II) nitrate + lead dioxide
Chemical names and formulas
| nitric acid | lead(II, IV) oxide | water | lead(II) nitrate | lead dioxide Hill formula | HNO_3 | O_4Pb_3 | H_2O | N_2O_6Pb | O_2Pb name | nitric acid | lead(II, IV) oxide | water | lead(II) nitrate | lead dioxide IUPAC name | nitric acid | lead tetraoxide | water | plumbous dinitrate |