Fe + H2S = H2 + FeS

Fe iron + H_2S hydrogen sulfide ⟶ H_2 hydrogen + FeS ferrous sulfide

Balance the chemical equation algebraically: Fe + H_2S ⟶ H_2 + FeS Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Fe + c_2 H_2S ⟶ c_3 H_2 + c_4 FeS Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, H and S: Fe: | c_1 = c_4 H: | 2 c_2 = 2 c_3 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Fe + H_2S ⟶ H_2 + FeS

+ ⟶ +

iron + hydrogen sulfide ⟶ hydrogen + ferrous sulfide

| iron | hydrogen sulfide | hydrogen | ferrous sulfide molecular enthalpy | 0 kJ/mol | -20.6 kJ/mol | 0 kJ/mol | -100 kJ/mol total enthalpy | 0 kJ/mol | -20.6 kJ/mol | 0 kJ/mol | -100 kJ/mol | H_initial = -20.6 kJ/mol | | H_final = -100 kJ/mol | ΔH_rxn^0 | -100 kJ/mol - -20.6 kJ/mol = -79.4 kJ/mol (exothermic) | | |

| iron | hydrogen sulfide | hydrogen | ferrous sulfide molecular entropy | 27 J/(mol K) | 206 J/(mol K) | 115 J/(mol K) | 67 J/(mol K) total entropy | 27 J/(mol K) | 206 J/(mol K) | 115 J/(mol K) | 67 J/(mol K) | S_initial = 233 J/(mol K) | | S_final = 182 J/(mol K) | ΔS_rxn^0 | 182 J/(mol K) - 233 J/(mol K) = -51 J/(mol K) (exoentropic) | | |

Construct the equilibrium constant, K, expression for: Fe + H_2S ⟶ H_2 + FeS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Fe + H_2S ⟶ H_2 + FeS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe | 1 | -1 H_2S | 1 | -1 H_2 | 1 | 1 FeS | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Fe | 1 | -1 | ([Fe])^(-1) H_2S | 1 | -1 | ([H2S])^(-1) H_2 | 1 | 1 | [H2] FeS | 1 | 1 | [FeS] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Fe])^(-1) ([H2S])^(-1) [H2] [FeS] = ([H2] [FeS])/([Fe] [H2S])

Construct the rate of reaction expression for: Fe + H_2S ⟶ H_2 + FeS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Fe + H_2S ⟶ H_2 + FeS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe | 1 | -1 H_2S | 1 | -1 H_2 | 1 | 1 FeS | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Fe | 1 | -1 | -(Δ[Fe])/(Δt) H_2S | 1 | -1 | -(Δ[H2S])/(Δt) H_2 | 1 | 1 | (Δ[H2])/(Δt) FeS | 1 | 1 | (Δ[FeS])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Fe])/(Δt) = -(Δ[H2S])/(Δt) = (Δ[H2])/(Δt) = (Δ[FeS])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| iron | hydrogen sulfide | hydrogen | ferrous sulfide formula | Fe | H_2S | H_2 | FeS name | iron | hydrogen sulfide | hydrogen | ferrous sulfide IUPAC name | iron | hydrogen sulfide | molecular hydrogen |

| iron | hydrogen sulfide | hydrogen | ferrous sulfide molar mass | 55.845 g/mol | 34.08 g/mol | 2.016 g/mol | 87.9 g/mol phase | solid (at STP) | gas (at STP) | gas (at STP) | solid (at STP) melting point | 1535 °C | -85 °C | -259.2 °C | 1195 °C boiling point | 2750 °C | -60 °C | -252.8 °C | density | 7.874 g/cm^3 | 0.001393 g/cm^3 (at 25 °C) | 8.99×10^-5 g/cm^3 (at 0 °C) | 4.84 g/cm^3 solubility in water | insoluble | | | insoluble dynamic viscosity | | 1.239×10^-5 Pa s (at 25 °C) | 8.9×10^-6 Pa s (at 25 °C) | 0.00343 Pa s (at 1250 °C) odor | | | odorless |