lithium selenide

lithium selenide

formula | Li_2Se name | lithium selenide mass fractions | Li (lithium) 14.9% | Se (selenium) 85.1%

Draw the Lewis structure of lithium selenide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the lithium (n_Li, val = 1) and selenium (n_Se, val = 6) atoms: 2 n_Li, val + n_Se, val = 8 Calculate the number of electrons needed to completely fill the valence shells for lithium (n_Li, full = 2) and selenium (n_Se, full = 8): 2 n_Li, full + n_Se, full = 12 Subtracting these two numbers shows that 12 - 8 = 4 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 2 bonds and hence 4 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 8 - 4 = 4 electrons left to draw: Answer: | |

molar mass | 92.9 g/mol

CAS number | 12136-60-6 PubChem CID number | 82935 SMILES identifier | [Li][Se][Li] InChI identifier | InChI=1/2Li.Se/rLi2Se/c1-3-2