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CO2 + Li = C + Li2O

Input interpretation

CO_2 carbon dioxide + Li lithium ⟶ C activated charcoal + Li_2O lithium oxide
CO_2 carbon dioxide + Li lithium ⟶ C activated charcoal + Li_2O lithium oxide

Balanced equation

Balance the chemical equation algebraically: CO_2 + Li ⟶ C + Li_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 CO_2 + c_2 Li ⟶ c_3 C + c_4 Li_2O Set the number of atoms in the reactants equal to the number of atoms in the products for C, O and Li: C: | c_1 = c_3 O: | 2 c_1 = c_4 Li: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 4 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | CO_2 + 4 Li ⟶ C + 2 Li_2O
Balance the chemical equation algebraically: CO_2 + Li ⟶ C + Li_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 CO_2 + c_2 Li ⟶ c_3 C + c_4 Li_2O Set the number of atoms in the reactants equal to the number of atoms in the products for C, O and Li: C: | c_1 = c_3 O: | 2 c_1 = c_4 Li: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 4 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | CO_2 + 4 Li ⟶ C + 2 Li_2O

Structures

 + ⟶ +
+ ⟶ +

Names

carbon dioxide + lithium ⟶ activated charcoal + lithium oxide
carbon dioxide + lithium ⟶ activated charcoal + lithium oxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: CO_2 + Li ⟶ C + Li_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: CO_2 + 4 Li ⟶ C + 2 Li_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 1 | -1 Li | 4 | -4 C | 1 | 1 Li_2O | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression CO_2 | 1 | -1 | ([CO2])^(-1) Li | 4 | -4 | ([Li])^(-4) C | 1 | 1 | [C] Li_2O | 2 | 2 | ([Li2O])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([CO2])^(-1) ([Li])^(-4) [C] ([Li2O])^2 = ([C] ([Li2O])^2)/([CO2] ([Li])^4)
Construct the equilibrium constant, K, expression for: CO_2 + Li ⟶ C + Li_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: CO_2 + 4 Li ⟶ C + 2 Li_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 1 | -1 Li | 4 | -4 C | 1 | 1 Li_2O | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression CO_2 | 1 | -1 | ([CO2])^(-1) Li | 4 | -4 | ([Li])^(-4) C | 1 | 1 | [C] Li_2O | 2 | 2 | ([Li2O])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([CO2])^(-1) ([Li])^(-4) [C] ([Li2O])^2 = ([C] ([Li2O])^2)/([CO2] ([Li])^4)

Rate of reaction

Construct the rate of reaction expression for: CO_2 + Li ⟶ C + Li_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: CO_2 + 4 Li ⟶ C + 2 Li_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 1 | -1 Li | 4 | -4 C | 1 | 1 Li_2O | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term CO_2 | 1 | -1 | -(Δ[CO2])/(Δt) Li | 4 | -4 | -1/4 (Δ[Li])/(Δt) C | 1 | 1 | (Δ[C])/(Δt) Li_2O | 2 | 2 | 1/2 (Δ[Li2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[CO2])/(Δt) = -1/4 (Δ[Li])/(Δt) = (Δ[C])/(Δt) = 1/2 (Δ[Li2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: CO_2 + Li ⟶ C + Li_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: CO_2 + 4 Li ⟶ C + 2 Li_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 1 | -1 Li | 4 | -4 C | 1 | 1 Li_2O | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term CO_2 | 1 | -1 | -(Δ[CO2])/(Δt) Li | 4 | -4 | -1/4 (Δ[Li])/(Δt) C | 1 | 1 | (Δ[C])/(Δt) Li_2O | 2 | 2 | 1/2 (Δ[Li2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[CO2])/(Δt) = -1/4 (Δ[Li])/(Δt) = (Δ[C])/(Δt) = 1/2 (Δ[Li2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | carbon dioxide | lithium | activated charcoal | lithium oxide formula | CO_2 | Li | C | Li_2O name | carbon dioxide | lithium | activated charcoal | lithium oxide IUPAC name | carbon dioxide | lithium | carbon | dilithium oxygen(-2) anion
| carbon dioxide | lithium | activated charcoal | lithium oxide formula | CO_2 | Li | C | Li_2O name | carbon dioxide | lithium | activated charcoal | lithium oxide IUPAC name | carbon dioxide | lithium | carbon | dilithium oxygen(-2) anion

Substance properties

 | carbon dioxide | lithium | activated charcoal | lithium oxide molar mass | 44.009 g/mol | 6.94 g/mol | 12.011 g/mol | 29.9 g/mol phase | gas (at STP) | solid (at STP) | solid (at STP) |  melting point | -56.56 °C (at triple point) | 180 °C | 3550 °C |  boiling point | -78.5 °C (at sublimation point) | 1342 °C | 4027 °C |  density | 0.00184212 g/cm^3 (at 20 °C) | 0.534 g/cm^3 | 2.26 g/cm^3 | 2.013 g/cm^3 solubility in water | | decomposes | insoluble |  surface tension | | 0.3975 N/m | |  dynamic viscosity | 1.491×10^-5 Pa s (at 25 °C) | | |  odor | odorless | | |
| carbon dioxide | lithium | activated charcoal | lithium oxide molar mass | 44.009 g/mol | 6.94 g/mol | 12.011 g/mol | 29.9 g/mol phase | gas (at STP) | solid (at STP) | solid (at STP) | melting point | -56.56 °C (at triple point) | 180 °C | 3550 °C | boiling point | -78.5 °C (at sublimation point) | 1342 °C | 4027 °C | density | 0.00184212 g/cm^3 (at 20 °C) | 0.534 g/cm^3 | 2.26 g/cm^3 | 2.013 g/cm^3 solubility in water | | decomposes | insoluble | surface tension | | 0.3975 N/m | | dynamic viscosity | 1.491×10^-5 Pa s (at 25 °C) | | | odor | odorless | | |

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