Input interpretation
niobium(V) fluoride | molar mass
Result
Find the molar mass, M, for niobium(V) fluoride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NbF_5 Use the chemical formula, NbF_5, to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 5 Nb (niobium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 5 | 18.998403163 Nb (niobium) | 1 | 92.90637 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 5 | 18.998403163 | 5 × 18.998403163 = 94.992015815 Nb (niobium) | 1 | 92.90637 | 1 × 92.90637 = 92.90637 M = 94.992015815 g/mol + 92.90637 g/mol = 187.89839 g/mol
Unit conversion
0.1878984 kg/mol (kilograms per mole)
Comparisons
≈ 0.26 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.97 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.1×10^-22 grams | 3.1×10^-25 kg (kilograms) | 188 u (unified atomic mass units) | 188 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 188