Input interpretation
ammonium bichromate | molar mass
Result
Find the molar mass, M, for ammonium bichromate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (NH_4)_2Cr_2O_7 Use the chemical formula, (NH_4)_2Cr_2O_7, to count the number of atoms, N_i, for each element: | N_i Cr (chromium) | 2 H (hydrogen) | 5 N (nitrogen) | 1 O (oxygen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cr (chromium) | 2 | 51.9961 H (hydrogen) | 5 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 7 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cr (chromium) | 2 | 51.9961 | 2 × 51.9961 = 103.9922 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 M = 103.9922 g/mol + 5.040 g/mol + 14.007 g/mol + 111.993 g/mol = 235.032 g/mol
Unit conversion
0.23503 kg/mol (kilograms per mole)
Comparisons
≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.9×10^-22 grams | 3.9×10^-25 kg (kilograms) | 235 u (unified atomic mass units) | 235 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 235