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molar mass of chloroplatinic acid

Input interpretation

chloroplatinic acid | molar mass
chloroplatinic acid | molar mass

Result

Find the molar mass, M, for chloroplatinic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2PtCl_6 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Cl (chlorine) | 6  H (hydrogen) | 4  O (oxygen) | 1  Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Cl (chlorine) | 6 | 35.45  H (hydrogen) | 4 | 1.008  O (oxygen) | 1 | 15.999  Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Cl (chlorine) | 6 | 35.45 | 6 × 35.45 = 212.70  H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032  O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999  Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084  M = 212.70 g/mol + 4.032 g/mol + 15.999 g/mol + 195.084 g/mol = 427.82 g/mol
Find the molar mass, M, for chloroplatinic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2PtCl_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 6 H (hydrogen) | 4 O (oxygen) | 1 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 6 | 35.45 H (hydrogen) | 4 | 1.008 O (oxygen) | 1 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 6 | 35.45 | 6 × 35.45 = 212.70 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 212.70 g/mol + 4.032 g/mol + 15.999 g/mol + 195.084 g/mol = 427.82 g/mol

Unit conversion

0.4278 kg/mol (kilograms per mole)
0.4278 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.59 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.59 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 7.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 7.3 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 7.1×10^-22 grams  | 7.1×10^-25 kg (kilograms)  | 428 u (unified atomic mass units)  | 428 Da (daltons)
Mass of a molecule m from m = M/N_A: | 7.1×10^-22 grams | 7.1×10^-25 kg (kilograms) | 428 u (unified atomic mass units) | 428 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 428
Relative molecular mass M_r from M_r = M_u/M: | 428