Input interpretation
![diamminedinitritoplatinum(II) | molar mass](../image_source/186397f936feedc2c96f335a4a16deb1.png)
diamminedinitritoplatinum(II) | molar mass
Result
![Find the molar mass, M, for diamminedinitritoplatinum(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pt(NH_3)_2(NO_2)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 N (nitrogen) | 4 O (oxygen) | 4 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 N (nitrogen) | 4 | 14.007 O (oxygen) | 4 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 6.048 g/mol + 56.028 g/mol + 63.996 g/mol + 195.084 g/mol = 321.156 g/mol](../image_source/d375c9302e9643313a18e4983afc7613.png)
Find the molar mass, M, for diamminedinitritoplatinum(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pt(NH_3)_2(NO_2)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 N (nitrogen) | 4 O (oxygen) | 4 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 N (nitrogen) | 4 | 14.007 O (oxygen) | 4 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 6.048 g/mol + 56.028 g/mol + 63.996 g/mol + 195.084 g/mol = 321.156 g/mol
Unit conversion
![0.32116 kg/mol (kilograms per mole)](../image_source/4c99b80b918309a66faa673f96b3c960.png)
0.32116 kg/mol (kilograms per mole)
Comparisons
![≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/f9c01fa79b15ab09d8f4398219d8d519.png)
≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/8bc6caf3ce83e6119cb980e2cb7d12b7.png)
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/3c005680a269cf4d9b41d558a4f8d7cd.png)
≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.3×10^-22 grams | 5.3×10^-25 kg (kilograms) | 321 u (unified atomic mass units) | 321 Da (daltons)](../image_source/76cec8fef21eea68ba1366e96da5710e.png)
Mass of a molecule m from m = M/N_A: | 5.3×10^-22 grams | 5.3×10^-25 kg (kilograms) | 321 u (unified atomic mass units) | 321 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 321](../image_source/b66df78a0103f28d27c31524fad06560.png)
Relative molecular mass M_r from M_r = M_u/M: | 321