Input interpretation
diamminedinitritoplatinum(II) | molar mass
Result
Find the molar mass, M, for diamminedinitritoplatinum(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pt(NH_3)_2(NO_2)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 N (nitrogen) | 4 O (oxygen) | 4 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 N (nitrogen) | 4 | 14.007 O (oxygen) | 4 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 6.048 g/mol + 56.028 g/mol + 63.996 g/mol + 195.084 g/mol = 321.156 g/mol
Unit conversion
0.32116 kg/mol (kilograms per mole)
Comparisons
≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.3×10^-22 grams | 5.3×10^-25 kg (kilograms) | 321 u (unified atomic mass units) | 321 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 321