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name of tetradecahydrophenanthrene

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tetradecahydrophenanthrene
tetradecahydrophenanthrene

Chemical names and formulas

formula | C_14H_24 name | tetradecahydrophenanthrene IUPAC name | 1, 2, 3, 4, 4a, 4b, 5, 6, 7, 8, 8a, 9, 10, 10a-tetradecahydrophenanthrene alternate names | perhydrophenanthrene | phenanthrene, tetradecahydro- | tricyclo[8.4.0.0(2, 7)]tetradecane mass fractions | C (carbon) 87.4% | H (hydrogen) 12.6%
formula | C_14H_24 name | tetradecahydrophenanthrene IUPAC name | 1, 2, 3, 4, 4a, 4b, 5, 6, 7, 8, 8a, 9, 10, 10a-tetradecahydrophenanthrene alternate names | perhydrophenanthrene | phenanthrene, tetradecahydro- | tricyclo[8.4.0.0(2, 7)]tetradecane mass fractions | C (carbon) 87.4% | H (hydrogen) 12.6%

Lewis structure

Draw the Lewis structure of tetradecahydrophenanthrene. Start by drawing the overall structure of the molecule:  Count the total valence electrons of the carbon (n_C, val = 4) and hydrogen (n_H, val = 1) atoms: 14 n_C, val + 24 n_H, val = 80 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8) and hydrogen (n_H, full = 2): 14 n_C, full + 24 n_H, full = 160 Subtracting these two numbers shows that 160 - 80 = 80 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 40 bonds and hence 80 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 80 - 80 = 0 electrons left to draw and the diagram is complete: Answer: |   |
Draw the Lewis structure of tetradecahydrophenanthrene. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4) and hydrogen (n_H, val = 1) atoms: 14 n_C, val + 24 n_H, val = 80 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8) and hydrogen (n_H, full = 2): 14 n_C, full + 24 n_H, full = 160 Subtracting these two numbers shows that 160 - 80 = 80 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 40 bonds and hence 80 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 80 - 80 = 0 electrons left to draw and the diagram is complete: Answer: | |

3D structure

3D structure
3D structure

Basic properties

molar mass | 192.35 g/mol phase | liquid (at STP) melting point | 13 °C boiling point | 272 °C density | 0.933 g/cm^3 solubility in water | insoluble
molar mass | 192.35 g/mol phase | liquid (at STP) melting point | 13 °C boiling point | 272 °C density | 0.933 g/cm^3 solubility in water | insoluble

Units

Liquid properties (at STP)

density | 0.933 g/cm^3 vapor pressure | 62.2 mmHg (at 181.5 °C) dynamic viscosity | 0.00797 Pa s (at 20 °C) refractive index | 1.5152
density | 0.933 g/cm^3 vapor pressure | 62.2 mmHg (at 181.5 °C) dynamic viscosity | 0.00797 Pa s (at 20 °C) refractive index | 1.5152

Units

Chemical identifiers

CAS number | 5743-97-5 Beilstein number | 2038162 PubChem CID number | 21971 SMILES identifier | C1CCC2C(C1)CCC3C2CCCC3 InChI identifier | InChI=1/C14H24/c1-3-7-13-11(5-1)9-10-12-6-2-4-8-14(12)13/h11-14H, 1-10H2 EU number | 227-267-8 NSC number | 91521
CAS number | 5743-97-5 Beilstein number | 2038162 PubChem CID number | 21971 SMILES identifier | C1CCC2C(C1)CCC3C2CCCC3 InChI identifier | InChI=1/C14H24/c1-3-7-13-11(5-1)9-10-12-6-2-4-8-14(12)13/h11-14H, 1-10H2 EU number | 227-267-8 NSC number | 91521