Input interpretation
![barium zirconate | molar mass](../image_source/e0923a1b8ab420a86149f480c8a27944.png)
barium zirconate | molar mass
Result
![Find the molar mass, M, for barium zirconate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BaZrO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ba (barium) | 1 O (oxygen) | 3 Zr (zirconium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ba (barium) | 1 | 137.327 O (oxygen) | 3 | 15.999 Zr (zirconium) | 1 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Zr (zirconium) | 1 | 91.224 | 1 × 91.224 = 91.224 M = 137.327 g/mol + 47.997 g/mol + 91.224 g/mol = 276.548 g/mol](../image_source/a0088aafb93f882e8c9b25fe77108a36.png)
Find the molar mass, M, for barium zirconate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BaZrO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ba (barium) | 1 O (oxygen) | 3 Zr (zirconium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ba (barium) | 1 | 137.327 O (oxygen) | 3 | 15.999 Zr (zirconium) | 1 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Zr (zirconium) | 1 | 91.224 | 1 × 91.224 = 91.224 M = 137.327 g/mol + 47.997 g/mol + 91.224 g/mol = 276.548 g/mol
Unit conversion
![0.27655 kg/mol (kilograms per mole)](../image_source/7d571c23fb30103189b0b840ba425f6d.png)
0.27655 kg/mol (kilograms per mole)
Comparisons
![≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/4a43f18b6fb1bd9f62359ddfc15e7fb4.png)
≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/02281f4297a96a836708a7d89ac4751b.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/bf770db06c51b812d42c6c2f5cb956b0.png)
≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.6×10^-22 grams | 4.6×10^-25 kg (kilograms) | 277 u (unified atomic mass units) | 277 Da (daltons)](../image_source/0f039cc0d0dc48df6712c92120aadcf9.png)
Mass of a molecule m from m = M/N_A: | 4.6×10^-22 grams | 4.6×10^-25 kg (kilograms) | 277 u (unified atomic mass units) | 277 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 277](../image_source/203ff0db0931542d02a9875610fbbf01.png)
Relative molecular mass M_r from M_r = M_u/M: | 277