Input interpretation
![sodium dibutyldithiocarbamate | molar mass](../image_source/6114281f1fa137746e3a44232505d5f2.png)
sodium dibutyldithiocarbamate | molar mass
Result
![Find the molar mass, M, for sodium dibutyldithiocarbamate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_9H_18NNaS_2 Use the chemical formula, C_9H_18NNaS_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 18 N (nitrogen) | 1 Na (sodium) | 1 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 18 | 1.008 N (nitrogen) | 1 | 14.007 Na (sodium) | 1 | 22.98976928 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 18 | 1.008 | 18 × 1.008 = 18.144 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 108.099 g/mol + 18.144 g/mol + 14.007 g/mol + 22.98976928 g/mol + 64.12 g/mol = 227.36 g/mol](../image_source/d27f06ddf7f62844f6d868a3e9ecf2af.png)
Find the molar mass, M, for sodium dibutyldithiocarbamate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_9H_18NNaS_2 Use the chemical formula, C_9H_18NNaS_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 18 N (nitrogen) | 1 Na (sodium) | 1 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 18 | 1.008 N (nitrogen) | 1 | 14.007 Na (sodium) | 1 | 22.98976928 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 18 | 1.008 | 18 × 1.008 = 18.144 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 108.099 g/mol + 18.144 g/mol + 14.007 g/mol + 22.98976928 g/mol + 64.12 g/mol = 227.36 g/mol
Unit conversion
![0.2274 kg/mol (kilograms per mole)](../image_source/a66a0fcd1e862a4a884f268ba84e1456.png)
0.2274 kg/mol (kilograms per mole)
Comparisons
![≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/f73bbeafb6011ade7a604d7eaf2a1f3b.png)
≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/b9764486f075fc02169c3393f0d0f2bc.png)
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/8907577e9843a4d7217237cf6f5cb769.png)
≈ 3.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 227 u (unified atomic mass units) | 227 Da (daltons)](../image_source/de75d0d67b616c93afef53deeacb73d9.png)
Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 227 u (unified atomic mass units) | 227 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 227](../image_source/68e94f20bf68ea8c91d60f3a202f240c.png)
Relative molecular mass M_r from M_r = M_u/M: | 227