Input interpretation
hypobromous acid
Chemical names and formulas
formula | HOBr Hill formula | BrHO name | hypobromous acid alternate names | bromanol | hypobromite mass fractions | Br (bromine) 82.5% | H (hydrogen) 1.04% | O (oxygen) 16.5%
Lewis structure
Draw the Lewis structure of hypobromous acid. Start by drawing the overall structure of the molecule: Count the total valence electrons of the bromine (n_Br, val = 7), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms: n_Br, val + n_H, val + n_O, val = 14 Calculate the number of electrons needed to completely fill the valence shells for bromine (n_Br, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): n_Br, full + n_H, full + n_O, full = 18 Subtracting these two numbers shows that 18 - 14 = 4 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 2 bonds and hence 4 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 14 - 4 = 10 electrons left to draw: Answer: | |
3D structure
3D structure
Basic properties
molar mass | 96.91 g/mol
Units
Chemical identifiers
PubChem CID number | 83547 SMILES identifier | OBr InChI identifier | InChI=1S/BrHO/c1-2/h2H