Input interpretation
![praseodymium(III) carbonate hydrate | molar mass](../image_source/07f28ab9db22fb1c00bcc96fc6371843.png)
praseodymium(III) carbonate hydrate | molar mass
Result
![Find the molar mass, M, for praseodymium(III) carbonate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pr_2(CO_3)_3·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 H (hydrogen) | 2 O (oxygen) | 10 Pr (praseodymium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 H (hydrogen) | 2 | 1.008 O (oxygen) | 10 | 15.999 Pr (praseodymium) | 2 | 140.90766 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 10 | 15.999 | 10 × 15.999 = 159.990 Pr (praseodymium) | 2 | 140.90766 | 2 × 140.90766 = 281.81532 M = 36.033 g/mol + 2.016 g/mol + 159.990 g/mol + 281.81532 g/mol = 479.854 g/mol](../image_source/3f238eb681933d5dec5e1d1019af0237.png)
Find the molar mass, M, for praseodymium(III) carbonate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pr_2(CO_3)_3·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 H (hydrogen) | 2 O (oxygen) | 10 Pr (praseodymium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 H (hydrogen) | 2 | 1.008 O (oxygen) | 10 | 15.999 Pr (praseodymium) | 2 | 140.90766 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 10 | 15.999 | 10 × 15.999 = 159.990 Pr (praseodymium) | 2 | 140.90766 | 2 × 140.90766 = 281.81532 M = 36.033 g/mol + 2.016 g/mol + 159.990 g/mol + 281.81532 g/mol = 479.854 g/mol
Unit conversion
![0.47985 kg/mol (kilograms per mole)](../image_source/36dbff1c74dd47cdf1ab056f6f53ff53.png)
0.47985 kg/mol (kilograms per mole)
Comparisons
![≈ 0.67 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/3ec9a59dd7b85457292a66ff6dcf8d6d.png)
≈ 0.67 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/54d2d494a0d94b6bfbe85ee188076be7.png)
≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 8.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/937763dc709fa626b7b7176144c37617.png)
≈ 8.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 8×10^-22 grams | 8×10^-25 kg (kilograms) | 480 u (unified atomic mass units) | 480 Da (daltons)](../image_source/0c021ed05d83fb1e9affff89121dd1cd.png)
Mass of a molecule m from m = M/N_A: | 8×10^-22 grams | 8×10^-25 kg (kilograms) | 480 u (unified atomic mass units) | 480 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 480](../image_source/7101f71a9a1d3b9f40ddc0a2c586edad.png)
Relative molecular mass M_r from M_r = M_u/M: | 480