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H2 + CO = H2O + CH4

Input interpretation

H_2 hydrogen + CO carbon monoxide ⟶ H_2O water + CH_4 methane
H_2 hydrogen + CO carbon monoxide ⟶ H_2O water + CH_4 methane

Balanced equation

Balance the chemical equation algebraically: H_2 + CO ⟶ H_2O + CH_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 CO ⟶ c_3 H_2O + c_4 CH_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, C and O: H: | 2 c_1 = 2 c_3 + 4 c_4 C: | c_2 = c_4 O: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 3 H_2 + CO ⟶ H_2O + CH_4
Balance the chemical equation algebraically: H_2 + CO ⟶ H_2O + CH_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 CO ⟶ c_3 H_2O + c_4 CH_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, C and O: H: | 2 c_1 = 2 c_3 + 4 c_4 C: | c_2 = c_4 O: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 H_2 + CO ⟶ H_2O + CH_4

Structures

 + ⟶ +
+ ⟶ +

Names

hydrogen + carbon monoxide ⟶ water + methane
hydrogen + carbon monoxide ⟶ water + methane

Reaction thermodynamics

Enthalpy

 | hydrogen | carbon monoxide | water | methane molecular enthalpy | 0 kJ/mol | -110.5 kJ/mol | -285.8 kJ/mol | -74.6 kJ/mol total enthalpy | 0 kJ/mol | -110.5 kJ/mol | -285.8 kJ/mol | -74.6 kJ/mol  | H_initial = -110.5 kJ/mol | | H_final = -360.4 kJ/mol |  ΔH_rxn^0 | -360.4 kJ/mol - -110.5 kJ/mol = -249.9 kJ/mol (exothermic) | | |
| hydrogen | carbon monoxide | water | methane molecular enthalpy | 0 kJ/mol | -110.5 kJ/mol | -285.8 kJ/mol | -74.6 kJ/mol total enthalpy | 0 kJ/mol | -110.5 kJ/mol | -285.8 kJ/mol | -74.6 kJ/mol | H_initial = -110.5 kJ/mol | | H_final = -360.4 kJ/mol | ΔH_rxn^0 | -360.4 kJ/mol - -110.5 kJ/mol = -249.9 kJ/mol (exothermic) | | |

Gibbs free energy

 | hydrogen | carbon monoxide | water | methane molecular free energy | 0 kJ/mol | -137 kJ/mol | -237.1 kJ/mol | -51 kJ/mol total free energy | 0 kJ/mol | -137 kJ/mol | -237.1 kJ/mol | -51 kJ/mol  | G_initial = -137 kJ/mol | | G_final = -288.1 kJ/mol |  ΔG_rxn^0 | -288.1 kJ/mol - -137 kJ/mol = -151.1 kJ/mol (exergonic) | | |
| hydrogen | carbon monoxide | water | methane molecular free energy | 0 kJ/mol | -137 kJ/mol | -237.1 kJ/mol | -51 kJ/mol total free energy | 0 kJ/mol | -137 kJ/mol | -237.1 kJ/mol | -51 kJ/mol | G_initial = -137 kJ/mol | | G_final = -288.1 kJ/mol | ΔG_rxn^0 | -288.1 kJ/mol - -137 kJ/mol = -151.1 kJ/mol (exergonic) | | |

Entropy

 | hydrogen | carbon monoxide | water | methane molecular entropy | 115 J/(mol K) | 198 J/(mol K) | 69.91 J/(mol K) | 186 J/(mol K) total entropy | 345 J/(mol K) | 198 J/(mol K) | 69.91 J/(mol K) | 186 J/(mol K)  | S_initial = 543 J/(mol K) | | S_final = 255.9 J/(mol K) |  ΔS_rxn^0 | 255.9 J/(mol K) - 543 J/(mol K) = -287.1 J/(mol K) (exoentropic) | | |
| hydrogen | carbon monoxide | water | methane molecular entropy | 115 J/(mol K) | 198 J/(mol K) | 69.91 J/(mol K) | 186 J/(mol K) total entropy | 345 J/(mol K) | 198 J/(mol K) | 69.91 J/(mol K) | 186 J/(mol K) | S_initial = 543 J/(mol K) | | S_final = 255.9 J/(mol K) | ΔS_rxn^0 | 255.9 J/(mol K) - 543 J/(mol K) = -287.1 J/(mol K) (exoentropic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2 + CO ⟶ H_2O + CH_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 H_2 + CO ⟶ H_2O + CH_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 CO | 1 | -1 H_2O | 1 | 1 CH_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 3 | -3 | ([H2])^(-3) CO | 1 | -1 | ([CO])^(-1) H_2O | 1 | 1 | [H2O] CH_4 | 1 | 1 | [CH4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2])^(-3) ([CO])^(-1) [H2O] [CH4] = ([H2O] [CH4])/(([H2])^3 [CO])
Construct the equilibrium constant, K, expression for: H_2 + CO ⟶ H_2O + CH_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 H_2 + CO ⟶ H_2O + CH_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 CO | 1 | -1 H_2O | 1 | 1 CH_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 3 | -3 | ([H2])^(-3) CO | 1 | -1 | ([CO])^(-1) H_2O | 1 | 1 | [H2O] CH_4 | 1 | 1 | [CH4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-3) ([CO])^(-1) [H2O] [CH4] = ([H2O] [CH4])/(([H2])^3 [CO])

Rate of reaction

Construct the rate of reaction expression for: H_2 + CO ⟶ H_2O + CH_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 H_2 + CO ⟶ H_2O + CH_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 CO | 1 | -1 H_2O | 1 | 1 CH_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 3 | -3 | -1/3 (Δ[H2])/(Δt) CO | 1 | -1 | -(Δ[CO])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) CH_4 | 1 | 1 | (Δ[CH4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/3 (Δ[H2])/(Δt) = -(Δ[CO])/(Δt) = (Δ[H2O])/(Δt) = (Δ[CH4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2 + CO ⟶ H_2O + CH_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 H_2 + CO ⟶ H_2O + CH_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 CO | 1 | -1 H_2O | 1 | 1 CH_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 3 | -3 | -1/3 (Δ[H2])/(Δt) CO | 1 | -1 | -(Δ[CO])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) CH_4 | 1 | 1 | (Δ[CH4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[H2])/(Δt) = -(Δ[CO])/(Δt) = (Δ[H2O])/(Δt) = (Δ[CH4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | hydrogen | carbon monoxide | water | methane formula | H_2 | CO | H_2O | CH_4 name | hydrogen | carbon monoxide | water | methane IUPAC name | molecular hydrogen | carbon monoxide | water | methane
| hydrogen | carbon monoxide | water | methane formula | H_2 | CO | H_2O | CH_4 name | hydrogen | carbon monoxide | water | methane IUPAC name | molecular hydrogen | carbon monoxide | water | methane