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volume of 12 kg of barium

Input interpretation

convert 12 kg of barium (chemical element) to volume
convert 12 kg of barium (chemical element) to volume

Results

3.419 L (liters)
3.419 L (liters)

Possible intermediate steps

Convert from kilograms into liters: 12 kg of Ba (barium) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 3.51 g/cm^3 (grams per cubic centimeter) at STP of Ba: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(3.51 g) = 3419 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (3419 cm^3)/1 × (1 mL)/(1 cm^3) = 3419 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: |   | (3419 mL)/1 × (1 L)/(1000 mL) = 3.419 L
Convert from kilograms into liters: 12 kg of Ba (barium) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 3.51 g/cm^3 (grams per cubic centimeter) at STP of Ba: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(3.51 g) = 3419 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (3419 cm^3)/1 × (1 mL)/(1 cm^3) = 3419 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: | | (3419 mL)/1 × (1 L)/(1000 mL) = 3.419 L

Unit conversions

0.003419 m^3 (cubic meters)
0.003419 m^3 (cubic meters)
3419 cm^3 (cubic centimeters)
3419 cm^3 (cubic centimeters)
7.225 pints
7.225 pints
3.613 quarts
3.613 quarts
0.9032 gallons
0.9032 gallons
0.1207 ft^3 (cubic feet)
0.1207 ft^3 (cubic feet)
208.6 in^3 (cubic inches)
208.6 in^3 (cubic inches)

Comparisons as volume

 ≈ 0.62 × volume of a soccer ball ( 5310 to 5792 cm^3 )
≈ 0.62 × volume of a soccer ball ( 5310 to 5792 cm^3 )
 ≈ 0.7 × volume of blood in a typical human ( ≈ 5 L )
≈ 0.7 × volume of blood in a typical human ( ≈ 5 L )
 ≈ 0.81 × volume of a American NFL football ( ≈ 259 in^3 )
≈ 0.81 × volume of a American NFL football ( ≈ 259 in^3 )

Comparisons as volume of food or beverage

 ≈ 1.1 × volume of a US size 10 can ( 105 fl oz )
≈ 1.1 × volume of a US size 10 can ( 105 fl oz )
 ≈ 2.1 × volume of a US size 5 can ( 7 cups )
≈ 2.1 × volume of a US size 5 can ( 7 cups )
 ≈ 3.6 × volume of a US size 3 can ( 4 cups )
≈ 3.6 × volume of a US size 3 can ( 4 cups )

Interpretations

volume
volume
volume of food or beverage
volume of food or beverage
section modulus
section modulus

Basic unit dimensions

[length]^3
[length]^3

Corresponding quantities

Radius r of a sphere from V = 4πr^3/3:  | 93 mm (millimeters)  | 0.31 feet  | 3.7 inches
Radius r of a sphere from V = 4πr^3/3: | 93 mm (millimeters) | 0.31 feet | 3.7 inches
Edge length a of a cube from V = a^3:  | 15 cm (centimeters)  | 0.49 feet  | 5.9 inches
Edge length a of a cube from V = a^3: | 15 cm (centimeters) | 0.49 feet | 5.9 inches
Mass m of water from m = ρ_(H_2O)V:  | 3.4 kg (kilograms)  | 7.5 lb (pounds)  | (assuming maximum water density ≈ 1000 kg/m^3)
Mass m of water from m = ρ_(H_2O)V: | 3.4 kg (kilograms) | 7.5 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O):  | 1.143×10^26 molecules  | (assuming maximum water density ≈ 1000 kg/m^3)  | (assuming molecular mass of water ≈ 18.02 u)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 1.143×10^26 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)