Input interpretation
![H_2 hydrogen + SO_3 sulfur trioxide ⟶ H_2O water + SO_2 sulfur dioxide](../image_source/585a661ab6ab81d1f4e0e4b5f02b1e8d.png)
H_2 hydrogen + SO_3 sulfur trioxide ⟶ H_2O water + SO_2 sulfur dioxide
Balanced equation
![Balance the chemical equation algebraically: H_2 + SO_3 ⟶ H_2O + SO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 SO_3 ⟶ c_3 H_2O + c_4 SO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and S: H: | 2 c_1 = 2 c_3 O: | 3 c_2 = c_3 + 2 c_4 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2 + SO_3 ⟶ H_2O + SO_2](../image_source/5320bc73e56c1ea27327ac55ef511a80.png)
Balance the chemical equation algebraically: H_2 + SO_3 ⟶ H_2O + SO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 SO_3 ⟶ c_3 H_2O + c_4 SO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and S: H: | 2 c_1 = 2 c_3 O: | 3 c_2 = c_3 + 2 c_4 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2 + SO_3 ⟶ H_2O + SO_2
Structures
![+ ⟶ +](../image_source/aac16b74e01be307035736986e15541a.png)
+ ⟶ +
Names
![hydrogen + sulfur trioxide ⟶ water + sulfur dioxide](../image_source/45debe4016b6b6bcf24837120381b740.png)
hydrogen + sulfur trioxide ⟶ water + sulfur dioxide
Reaction thermodynamics
Gibbs free energy
![| hydrogen | sulfur trioxide | water | sulfur dioxide molecular free energy | 0 kJ/mol | -373.8 kJ/mol | -237.1 kJ/mol | -300.1 kJ/mol total free energy | 0 kJ/mol | -373.8 kJ/mol | -237.1 kJ/mol | -300.1 kJ/mol | G_initial = -373.8 kJ/mol | | G_final = -537.2 kJ/mol | ΔG_rxn^0 | -537.2 kJ/mol - -373.8 kJ/mol = -163.4 kJ/mol (exergonic) | | |](../image_source/8a264c6b7504892b0cda75a34dd143de.png)
| hydrogen | sulfur trioxide | water | sulfur dioxide molecular free energy | 0 kJ/mol | -373.8 kJ/mol | -237.1 kJ/mol | -300.1 kJ/mol total free energy | 0 kJ/mol | -373.8 kJ/mol | -237.1 kJ/mol | -300.1 kJ/mol | G_initial = -373.8 kJ/mol | | G_final = -537.2 kJ/mol | ΔG_rxn^0 | -537.2 kJ/mol - -373.8 kJ/mol = -163.4 kJ/mol (exergonic) | | |
Equilibrium constant
![Construct the equilibrium constant, K, expression for: H_2 + SO_3 ⟶ H_2O + SO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2 + SO_3 ⟶ H_2O + SO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 SO_3 | 1 | -1 H_2O | 1 | 1 SO_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 1 | -1 | ([H2])^(-1) SO_3 | 1 | -1 | ([SO3])^(-1) H_2O | 1 | 1 | [H2O] SO_2 | 1 | 1 | [SO2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-1) ([SO3])^(-1) [H2O] [SO2] = ([H2O] [SO2])/([H2] [SO3])](../image_source/8b2e297f46506906c071916dd9127f1d.png)
Construct the equilibrium constant, K, expression for: H_2 + SO_3 ⟶ H_2O + SO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2 + SO_3 ⟶ H_2O + SO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 SO_3 | 1 | -1 H_2O | 1 | 1 SO_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 1 | -1 | ([H2])^(-1) SO_3 | 1 | -1 | ([SO3])^(-1) H_2O | 1 | 1 | [H2O] SO_2 | 1 | 1 | [SO2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-1) ([SO3])^(-1) [H2O] [SO2] = ([H2O] [SO2])/([H2] [SO3])
Rate of reaction
![Construct the rate of reaction expression for: H_2 + SO_3 ⟶ H_2O + SO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2 + SO_3 ⟶ H_2O + SO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 SO_3 | 1 | -1 H_2O | 1 | 1 SO_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 1 | -1 | -(Δ[H2])/(Δt) SO_3 | 1 | -1 | -(Δ[SO3])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) SO_2 | 1 | 1 | (Δ[SO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2])/(Δt) = -(Δ[SO3])/(Δt) = (Δ[H2O])/(Δt) = (Δ[SO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/610d41d67c8c3f2dfb7daa80732b472f.png)
Construct the rate of reaction expression for: H_2 + SO_3 ⟶ H_2O + SO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2 + SO_3 ⟶ H_2O + SO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 1 | -1 SO_3 | 1 | -1 H_2O | 1 | 1 SO_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 1 | -1 | -(Δ[H2])/(Δt) SO_3 | 1 | -1 | -(Δ[SO3])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) SO_2 | 1 | 1 | (Δ[SO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2])/(Δt) = -(Δ[SO3])/(Δt) = (Δ[H2O])/(Δt) = (Δ[SO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| hydrogen | sulfur trioxide | water | sulfur dioxide formula | H_2 | SO_3 | H_2O | SO_2 Hill formula | H_2 | O_3S | H_2O | O_2S name | hydrogen | sulfur trioxide | water | sulfur dioxide IUPAC name | molecular hydrogen | sulfur trioxide | water | sulfur dioxide](../image_source/e5c086156776ee09ac3bd0afc1556e5d.png)
| hydrogen | sulfur trioxide | water | sulfur dioxide formula | H_2 | SO_3 | H_2O | SO_2 Hill formula | H_2 | O_3S | H_2O | O_2S name | hydrogen | sulfur trioxide | water | sulfur dioxide IUPAC name | molecular hydrogen | sulfur trioxide | water | sulfur dioxide