Input interpretation
![difluoroethane | molar mass](../image_source/b964d577b5ea6052e63772f5b6b2e6e8.png)
difluoroethane | molar mass
Result
![Find the molar mass, M, for difluoroethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CHF_2 Use the chemical formula, CH_3CHF_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 2 F (fluorine) | 2 H (hydrogen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 2 | 12.011 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 4 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 2 | 12.011 | 2 × 12.011 = 24.022 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 M = 24.022 g/mol + 37.996806326 g/mol + 4.032 g/mol = 66.051 g/mol](../image_source/44d717a4047885441d7c7efc5b4c4915.png)
Find the molar mass, M, for difluoroethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CHF_2 Use the chemical formula, CH_3CHF_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 2 F (fluorine) | 2 H (hydrogen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 2 | 12.011 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 4 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 2 | 12.011 | 2 × 12.011 = 24.022 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 M = 24.022 g/mol + 37.996806326 g/mol + 4.032 g/mol = 66.051 g/mol
Unit conversion
![0.066051 kg/mol (kilograms per mole)](../image_source/3d82e1b2ef66e3c090bb5bae0c33c76a.png)
0.066051 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.092 ≈ 1/11 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/5fed091ca5b87ea8b66204e60b5fe75b.png)
≈ ( 0.092 ≈ 1/11 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.34 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/35e6cf8b2efe90455565bea52da94d94.png)
≈ 0.34 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/ecc4b6ed79fe2e1c02ab927d67b49cd4.png)
≈ 1.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.1×10^-22 grams | 1.1×10^-25 kg (kilograms) | 66 u (unified atomic mass units) | 66 Da (daltons)](../image_source/b803e88133c7fee940b37196acb97be9.png)
Mass of a molecule m from m = M/N_A: | 1.1×10^-22 grams | 1.1×10^-25 kg (kilograms) | 66 u (unified atomic mass units) | 66 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 66](../image_source/6c32533df49595612b7c0ca20e438beb.png)
Relative molecular mass M_r from M_r = M_u/M: | 66