Input interpretation
![trimethylphenylphosphonium iodide | molar mass](../image_source/eafda01a858a357aec5271d0a79568db.png)
trimethylphenylphosphonium iodide | molar mass
Result
![Find the molar mass, M, for trimethylphenylphosphonium iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5P(CH_3)_3I Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 14 I (iodine) | 1 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 14 | 1.008 I (iodine) | 1 | 126.90447 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 108.099 g/mol + 14.112 g/mol + 126.90447 g/mol + 30.973761998 g/mol = 280.089 g/mol](../image_source/7262fd56bb72d9cb89243850a80ca5f0.png)
Find the molar mass, M, for trimethylphenylphosphonium iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5P(CH_3)_3I Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 14 I (iodine) | 1 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 14 | 1.008 I (iodine) | 1 | 126.90447 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 108.099 g/mol + 14.112 g/mol + 126.90447 g/mol + 30.973761998 g/mol = 280.089 g/mol
Unit conversion
![0.28009 kg/mol (kilograms per mole)](../image_source/ab78cd62b726957f6b18789d20a81b76.png)
0.28009 kg/mol (kilograms per mole)
Comparisons
![≈ 0.39 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/1a49eb6ce6342d442ba4e992b8a8a61a.png)
≈ 0.39 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/6103dcd64ce970fbc426165428b5fdc1.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/28991771cddac3c45ce024204289079f.png)
≈ 4.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.7×10^-22 grams | 4.7×10^-25 kg (kilograms) | 280 u (unified atomic mass units) | 280 Da (daltons)](../image_source/4cd747163cfe3780a230ed953fb5cca9.png)
Mass of a molecule m from m = M/N_A: | 4.7×10^-22 grams | 4.7×10^-25 kg (kilograms) | 280 u (unified atomic mass units) | 280 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 280](../image_source/e43ef6b5725c7e8c9963dba089fe625d.png)
Relative molecular mass M_r from M_r = M_u/M: | 280