Input interpretation
![9-phenanthrylmagnesium bromide | molar mass](../image_source/283b8302d07724007cc9e017e0357e5c.png)
9-phenanthrylmagnesium bromide | molar mass
Result
![Find the molar mass, M, for 9-phenanthrylmagnesium bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_9BrMg Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 14 H (hydrogen) | 9 Mg (magnesium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 14 | 12.011 H (hydrogen) | 9 | 1.008 Mg (magnesium) | 1 | 24.305 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 Mg (magnesium) | 1 | 24.305 | 1 × 24.305 = 24.305 M = 79.904 g/mol + 168.154 g/mol + 9.072 g/mol + 24.305 g/mol = 281.435 g/mol](../image_source/38007d37b84324a69370bf146ec90e51.png)
Find the molar mass, M, for 9-phenanthrylmagnesium bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_9BrMg Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 14 H (hydrogen) | 9 Mg (magnesium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 14 | 12.011 H (hydrogen) | 9 | 1.008 Mg (magnesium) | 1 | 24.305 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 Mg (magnesium) | 1 | 24.305 | 1 × 24.305 = 24.305 M = 79.904 g/mol + 168.154 g/mol + 9.072 g/mol + 24.305 g/mol = 281.435 g/mol
Unit conversion
![0.28143 kg/mol (kilograms per mole)](../image_source/758b559e6f7bb06353e1a72dcbd7388b.png)
0.28143 kg/mol (kilograms per mole)
Comparisons
![≈ 0.39 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/32a07ae904b3c11a5f7aea73f8a108fe.png)
≈ 0.39 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/cefc7803a43816d3ba6dafad63ae60dd.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/9479abc83359735387a19a819b10b5cd.png)
≈ 4.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.7×10^-22 grams | 4.7×10^-25 kg (kilograms) | 281 u (unified atomic mass units) | 281 Da (daltons)](../image_source/e2a914ff9266cdf72203ba9f37197a1f.png)
Mass of a molecule m from m = M/N_A: | 4.7×10^-22 grams | 4.7×10^-25 kg (kilograms) | 281 u (unified atomic mass units) | 281 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 281](../image_source/5bf2422242b3804e04a81768c21a79d5.png)
Relative molecular mass M_r from M_r = M_u/M: | 281