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Fe(NO3)3 = O2 + NO2 + Fe2O3

Input interpretation

Fe(NO_3)_3 (ferric nitrate) ⟶ O_2 (oxygen) + NO_2 (nitrogen dioxide) + Fe_2O_3 (iron(III) oxide)
Fe(NO_3)_3 (ferric nitrate) ⟶ O_2 (oxygen) + NO_2 (nitrogen dioxide) + Fe_2O_3 (iron(III) oxide)

Balanced equation

Balance the chemical equation algebraically: Fe(NO_3)_3 ⟶ O_2 + NO_2 + Fe_2O_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Fe(NO_3)_3 ⟶ c_2 O_2 + c_3 NO_2 + c_4 Fe_2O_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, N and O: Fe: | c_1 = 2 c_4 N: | 3 c_1 = c_3 O: | 9 c_1 = 2 c_2 + 2 c_3 + 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 3/2 c_3 = 6 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 4 c_2 = 3 c_3 = 12 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 4 Fe(NO_3)_3 ⟶ 3 O_2 + 12 NO_2 + 2 Fe_2O_3
Balance the chemical equation algebraically: Fe(NO_3)_3 ⟶ O_2 + NO_2 + Fe_2O_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Fe(NO_3)_3 ⟶ c_2 O_2 + c_3 NO_2 + c_4 Fe_2O_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, N and O: Fe: | c_1 = 2 c_4 N: | 3 c_1 = c_3 O: | 9 c_1 = 2 c_2 + 2 c_3 + 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 3/2 c_3 = 6 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 4 c_2 = 3 c_3 = 12 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 Fe(NO_3)_3 ⟶ 3 O_2 + 12 NO_2 + 2 Fe_2O_3

Structures

 ⟶ + +
⟶ + +

Names

ferric nitrate ⟶ oxygen + nitrogen dioxide + iron(III) oxide
ferric nitrate ⟶ oxygen + nitrogen dioxide + iron(III) oxide

Equilibrium constant

K_c = ([O2]^3 [NO2]^12 [Fe2O3]^2)/[Fe(NO3)3]^4
K_c = ([O2]^3 [NO2]^12 [Fe2O3]^2)/[Fe(NO3)3]^4

Rate of reaction

rate = -1/4 (Δ[Fe(NO3)3])/(Δt) = 1/3 (Δ[O2])/(Δt) = 1/12 (Δ[NO2])/(Δt) = 1/2 (Δ[Fe2O3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
rate = -1/4 (Δ[Fe(NO3)3])/(Δt) = 1/3 (Δ[O2])/(Δt) = 1/12 (Δ[NO2])/(Δt) = 1/2 (Δ[Fe2O3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | ferric nitrate | oxygen | nitrogen dioxide | iron(III) oxide formula | Fe(NO_3)_3 | O_2 | NO_2 | Fe_2O_3 Hill formula | FeN_3O_9 | O_2 | NO_2 | Fe_2O_3 name | ferric nitrate | oxygen | nitrogen dioxide | iron(III) oxide IUPAC name | iron(+3) cation trinitrate | molecular oxygen | Nitrogen dioxide |
| ferric nitrate | oxygen | nitrogen dioxide | iron(III) oxide formula | Fe(NO_3)_3 | O_2 | NO_2 | Fe_2O_3 Hill formula | FeN_3O_9 | O_2 | NO_2 | Fe_2O_3 name | ferric nitrate | oxygen | nitrogen dioxide | iron(III) oxide IUPAC name | iron(+3) cation trinitrate | molecular oxygen | Nitrogen dioxide |

Substance properties

 | ferric nitrate | oxygen | nitrogen dioxide | iron(III) oxide molar mass | 241.86 g/mol | 31.998 g/mol | 46.005 g/mol | 159.69 g/mol phase | solid (at STP) | gas (at STP) | gas (at STP) | solid (at STP) melting point | 35 °C | -218 °C | -11 °C | 1565 °C boiling point | | -183 °C | 21 °C |  density | 1.7 g/cm^3 | 0.001429 g/cm^3 (at 0 °C) | 0.00188 g/cm^3 (at 25 °C) | 5.26 g/cm^3 solubility in water | very soluble | | reacts | insoluble surface tension | | 0.01347 N/m | |  dynamic viscosity | | 2.055×10^-5 Pa s (at 25 °C) | 4.02×10^-4 Pa s (at 25 °C) |  odor | | odorless | | odorless
| ferric nitrate | oxygen | nitrogen dioxide | iron(III) oxide molar mass | 241.86 g/mol | 31.998 g/mol | 46.005 g/mol | 159.69 g/mol phase | solid (at STP) | gas (at STP) | gas (at STP) | solid (at STP) melting point | 35 °C | -218 °C | -11 °C | 1565 °C boiling point | | -183 °C | 21 °C | density | 1.7 g/cm^3 | 0.001429 g/cm^3 (at 0 °C) | 0.00188 g/cm^3 (at 25 °C) | 5.26 g/cm^3 solubility in water | very soluble | | reacts | insoluble surface tension | | 0.01347 N/m | | dynamic viscosity | | 2.055×10^-5 Pa s (at 25 °C) | 4.02×10^-4 Pa s (at 25 °C) | odor | | odorless | | odorless

Units