Input interpretation
barium chlorate | relative molecular mass
Result
Find the relative molecular mass, M_r, for barium chlorate: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BaCl_2O_6 Use the chemical formula, BaCl_2O_6, to count the number of atoms, N_i, for each element: | N_i Ba (barium) | 1 Cl (chlorine) | 2 O (oxygen) | 6 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass: | N_i | m_i/m_u Ba (barium) | 1 | 137.327 Cl (chlorine) | 2 | 35.45 O (oxygen) | 6 | 15.999 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: | | | N_i | m_i/m_u | relative mass Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M_r = 137.327 + 70.90 + 95.994 = 304.22
Comparisons
≈ 0.42 × relative molecular mass of fullerene ( ≈ 721 )
≈ 1.6 × relative molecular mass of caffeine ( ≈ 194 )
≈ 5.2 × relative molecular mass of sodium chloride ( ≈ 58 )
Corresponding quantities
Molar mass M from M = M_uM_r: | 304 g/mol (grams per mole)
Molecular mass m from m = M_rM_u/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms)