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molar mass of SMILES:BrNO

Input interpretation

SMILES: BrNO | molar mass
SMILES: BrNO | molar mass

Result

Find the molar mass, M, for SMILES:BrNO: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrH_2NO Use the chemical formula to count the number of atoms, N_i, for each element:  | number of atoms  Br (bromine) | 1  N (nitrogen) | 1  O (oxygen) | 1  H (hydrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | number of atoms | atomic mass/g·mol^(-1)  Br (bromine) | 1 | 79.904  N (nitrogen) | 1 | 14.007  O (oxygen) | 1 | 15.999  H (hydrogen) | 2 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | number of atoms | atomic mass/g·mol^(-1) | mass/g·mol^(-1)  Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904  N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007  O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999  H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016  M = 79.904 g/mol + 14.007 g/mol + 15.999 g/mol + 2.016 g/mol = 111.926 g/mol
Find the molar mass, M, for SMILES:BrNO: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrH_2NO Use the chemical formula to count the number of atoms, N_i, for each element: | number of atoms Br (bromine) | 1 N (nitrogen) | 1 O (oxygen) | 1 H (hydrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | number of atoms | atomic mass/g·mol^(-1) Br (bromine) | 1 | 79.904 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 H (hydrogen) | 2 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | number of atoms | atomic mass/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 M = 79.904 g/mol + 14.007 g/mol + 15.999 g/mol + 2.016 g/mol = 111.926 g/mol

Unit conversion

0.1119 kg/mol (kilograms per mole)
0.1119 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.16 ≈ 1/6 ) × molar mass of fullerene (≈ 721 g/mol )
≈ ( 0.16 ≈ 1/6 ) × molar mass of fullerene (≈ 721 g/mol )
 ≈ 0.58 × molar mass of caffeine (≈ 194 g/mol )
≈ 0.58 × molar mass of caffeine (≈ 194 g/mol )
 ≈ 1.9 × molar mass of sodium chloride (≈ 58 g/mol )
≈ 1.9 × molar mass of sodium chloride (≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 1.9×10^-22 grams  | 1.9×10^-25 kg (kilograms)  | 112 u (unified atomic mass units)  | 112 Da (daltons)
Mass of a molecule m from m = M/N_A: | 1.9×10^-22 grams | 1.9×10^-25 kg (kilograms) | 112 u (unified atomic mass units) | 112 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 112
Relative molecular mass M_r from M_r = M_u/M: | 112