Input interpretation
diamminedibromopalladium(II) | molar mass
Result
Find the molar mass, M, for diamminedibromopalladium(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pd(NH_3)_2Br_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 2 H (hydrogen) | 6 N (nitrogen) | 2 Pd (palladium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 2 | 79.904 H (hydrogen) | 6 | 1.008 N (nitrogen) | 2 | 14.007 Pd (palladium) | 1 | 106.42 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 2 | 79.904 | 2 × 79.904 = 159.808 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 Pd (palladium) | 1 | 106.42 | 1 × 106.42 = 106.42 M = 159.808 g/mol + 6.048 g/mol + 28.014 g/mol + 106.42 g/mol = 300.29 g/mol
Unit conversion
0.30029 kg/mol (kilograms per mole)
Comparisons
≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 300 u (unified atomic mass units) | 300 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 300