Input interpretation
![2-acrylamidoglycolic acid monohydrate | molar mass](../image_source/fb0c25bb25e379a3a7e768bf42227ed5.png)
2-acrylamidoglycolic acid monohydrate | molar mass
Result
![Find the molar mass, M, for 2-acrylamidoglycolic acid monohydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=CHCONHCH(OH)CO_2H·H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 5 H (hydrogen) | 9 N (nitrogen) | 1 O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 5 | 12.011 H (hydrogen) | 9 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 M = 60.055 g/mol + 9.072 g/mol + 14.007 g/mol + 79.995 g/mol = 163.129 g/mol](../image_source/cbf1d50e513f76320d2cb96b4e2c7f19.png)
Find the molar mass, M, for 2-acrylamidoglycolic acid monohydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=CHCONHCH(OH)CO_2H·H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 5 H (hydrogen) | 9 N (nitrogen) | 1 O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 5 | 12.011 H (hydrogen) | 9 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 M = 60.055 g/mol + 9.072 g/mol + 14.007 g/mol + 79.995 g/mol = 163.129 g/mol
Unit conversion
![0.16313 kg/mol (kilograms per mole)](../image_source/79d973ade1de601a784a2f45b320b1e6.png)
0.16313 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/0696e0ef73ed557a1a37a166f87774cd.png)
≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.84 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/220145ae311f42a9ebdc5fc704c13cbc.png)
≈ 0.84 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/34a1bbfeb947473812093382caac8ea2.png)
≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 163 u (unified atomic mass units) | 163 Da (daltons)](../image_source/ede030ea7f353668e1e0529588ca3850.png)
Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 163 u (unified atomic mass units) | 163 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 163](../image_source/866098661f5de09b0280a6283808018b.png)
Relative molecular mass M_r from M_r = M_u/M: | 163