Input interpretation
4-iodobenzaldehyde
Chemical names and formulas
formula | IC_6H_4CHO Hill formula | C_7H_5IO name | 4-iodobenzaldehyde mass fractions | C (carbon) 36.2% | H (hydrogen) 2.17% | I (iodine) 54.7% | O (oxygen) 6.9%
Lewis structure
Draw the Lewis structure of 4-iodobenzaldehyde. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), iodine (n_I, val = 7), and oxygen (n_O, val = 6) atoms: 7 n_C, val + 5 n_H, val + n_I, val + n_O, val = 46 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), iodine (n_I, full = 8), and oxygen (n_O, full = 8): 7 n_C, full + 5 n_H, full + n_I, full + n_O, full = 82 Subtracting these two numbers shows that 82 - 46 = 36 bonding electrons are needed. Each bond has two electrons, so in addition to the 14 bonds already present in the diagram add 4 bonds. To minimize formal charge oxygen wants 2 bonds and carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom: Fill in the 4 bonds by pairing electrons between adjacent highlighted atoms. Note that the six atom ring is aromatic, so that the single and double bonds may be rearranged: Answer: | |
3D structure
3D structure
Basic properties
molar mass | 232.02 g/mol phase | solid (at STP) melting point | 80 °C
Units
Chemical identifiers
CAS number | 15164-44-0 PubChem CID number | 96657 PubChem SID number | 24855886 SMILES identifier | C1=CC(=CC=C1C=O)I InChI identifier | InChI=1/C7H5IO/c8-7-3-1-6(5-9)2-4-7/h1-5H MDL number | MFCD00039576