Input interpretation
![diiodomethane-d 2](../image_source/ccbfb02e5be553232eeab00b224739a8.png)
diiodomethane-d 2
Chemical names and formulas
![formula | CD_2I_2 name | diiodomethane-d 2 IUPAC name | dideuterio-diiodomethane alternate names | dideuterio-diiodo-methane | dideuterio-diiodomethane | methylene-d2 iodide mass fractions | I (iodine) 0.941% | C (carbon) 0.0445% | H (hydrogen) 0.0149%](../image_source/2a8b27489ce556d17c0872bff403c180.png)
formula | CD_2I_2 name | diiodomethane-d 2 IUPAC name | dideuterio-diiodomethane alternate names | dideuterio-diiodo-methane | dideuterio-diiodomethane | methylene-d2 iodide mass fractions | I (iodine) 0.941% | C (carbon) 0.0445% | H (hydrogen) 0.0149%
Lewis structure
![Draw the Lewis structure of diiodomethane-d 2. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and iodine (n_I, val = 7) atoms: n_C, val + 2 n_H, val + 2 n_I, val = 20 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and iodine (n_I, full = 8): n_C, full + 2 n_H, full + 2 n_I, full = 28 Subtracting these two numbers shows that 28 - 20 = 8 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 4 bonds and hence 8 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 20 - 8 = 12 electrons left to draw: Answer: | |](../image_source/f43abe3ea610a9a79301a851abb2884c.png)
Draw the Lewis structure of diiodomethane-d 2. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and iodine (n_I, val = 7) atoms: n_C, val + 2 n_H, val + 2 n_I, val = 20 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and iodine (n_I, full = 8): n_C, full + 2 n_H, full + 2 n_I, full = 28 Subtracting these two numbers shows that 28 - 20 = 8 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 4 bonds and hence 8 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 20 - 8 = 12 electrons left to draw: Answer: | |
3D structure
![3D structure](../image_source/65aaa4dffbdfe9a8cfdd4ae4ec77c718.png)
3D structure
Basic properties
![molar mass | 269.848 g/mol phase | liquid (at STP) boiling point | 68 °C (measured at 2000 Pa) density | 3.325 g/cm^3](../image_source/8c16aabeac25c49bfdaad42269640399.png)
molar mass | 269.848 g/mol phase | liquid (at STP) boiling point | 68 °C (measured at 2000 Pa) density | 3.325 g/cm^3
Units
Liquid properties (at STP)
![density | 3.325 g/cm^3](../image_source/3ef564ec85644cb2d724221ee3951416.png)
density | 3.325 g/cm^3
Units
Non-standard atom properties
![H-2 | 2](../image_source/18c40b9a5ffa6763bf8f3d1ce7dbab6e.png)
H-2 | 2
Chemical identifiers
![CAS number | 15729-58-5 PubChem CID number | 12403101 PubChem SID number | 24862348 SMILES identifier | C(I)I InChI identifier | InChI=1/CH2I2/c2-1-3/h1H2/i1D2 MDL number | MFCD00134252](../image_source/b9d66121bdb9fee50d22bc37a21a50eb.png)
CAS number | 15729-58-5 PubChem CID number | 12403101 PubChem SID number | 24862348 SMILES identifier | C(I)I InChI identifier | InChI=1/CH2I2/c2-1-3/h1H2/i1D2 MDL number | MFCD00134252
Safety properties
![flash point | 110 °C](../image_source/c241e24cde7081caeb200d96ee54b70a.png)
flash point | 110 °C