Input interpretation
magnesium carbonate hydroxide pentahydrate | molar mass
Result
Find the molar mass, M, for magnesium carbonate hydroxide pentahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_12MgO_9 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 9 C (carbon) | 1 Mg (magnesium) | 1 H (hydrogen) | 12 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 9 | 15.999 C (carbon) | 1 | 12.011 Mg (magnesium) | 1 | 24.305 H (hydrogen) | 12 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 Mg (magnesium) | 1 | 24.305 | 1 × 24.305 = 24.305 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 M = 143.991 g/mol + 12.011 g/mol + 24.305 g/mol + 12.096 g/mol = 192.403 g/mol