PbO2 = O2 + PbO

PbO_2 (lead dioxide) ⟶ O_2 (oxygen) + PbO (lead monoxide)

Balance the chemical equation algebraically: PbO_2 ⟶ O_2 + PbO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 PbO_2 ⟶ c_2 O_2 + c_3 PbO Set the number of atoms in the reactants equal to the number of atoms in the products for O and Pb: O: | 2 c_1 = 2 c_2 + c_3 Pb: | c_1 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 PbO_2 ⟶ O_2 + 2 PbO

⟶ +

lead dioxide ⟶ oxygen + lead monoxide

K_c = ([O2] [PbO]^2)/[PbO2]^2

rate = -1/2 (Δ[PbO2])/(Δt) = (Δ[O2])/(Δt) = 1/2 (Δ[PbO])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| lead dioxide | oxygen | lead monoxide formula | PbO_2 | O_2 | PbO Hill formula | O_2Pb | O_2 | OPb name | lead dioxide | oxygen | lead monoxide IUPAC name | | molecular oxygen |

| lead dioxide | oxygen | lead monoxide molar mass | 239.2 g/mol | 31.998 g/mol | 223.2 g/mol phase | solid (at STP) | gas (at STP) | solid (at STP) melting point | 290 °C | -218 °C | 886 °C boiling point | | -183 °C | 1470 °C density | 9.58 g/cm^3 | 0.001429 g/cm^3 (at 0 °C) | 9.5 g/cm^3 solubility in water | insoluble | | insoluble surface tension | | 0.01347 N/m | dynamic viscosity | | 2.055×10^-5 Pa s (at 25 °C) | 1.45×10^-4 Pa s (at 1000 °C) odor | | odorless |