Input interpretation
titanium(IV) nitrate | molar mass
Result
Find the molar mass, M, for titanium(IV) nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ti(NO_3)_4 Use the chemical formula, Ti(NO_3)_4, to count the number of atoms, N_i, for each element: | N_i N (nitrogen) | 4 O (oxygen) | 12 Ti (titanium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) N (nitrogen) | 4 | 14.007 O (oxygen) | 12 | 15.999 Ti (titanium) | 1 | 47.867 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 12 | 15.999 | 12 × 15.999 = 191.988 Ti (titanium) | 1 | 47.867 | 1 × 47.867 = 47.867 M = 56.028 g/mol + 191.988 g/mol + 47.867 g/mol = 295.883 g/mol
Unit conversion
0.29588 kg/mol (kilograms per mole)
Comparisons
≈ 0.41 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 4.9×10^-22 grams | 4.9×10^-25 kg (kilograms) | 296 u (unified atomic mass units) | 296 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 296