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H2SO4 + H2S + K2Cr2O7 = H2O + K2SO4 + S + Cr(SO4)3

Input interpretation

sulfuric acid + hydrogen sulfide + potassium dichromate ⟶ water + potassium sulfate + mixed sulfur + Cr(SO4)3
sulfuric acid + hydrogen sulfide + potassium dichromate ⟶ water + potassium sulfate + mixed sulfur + Cr(SO4)3

Balanced equation

Balance the chemical equation algebraically:  + + ⟶ + + + Cr(SO4)3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Cr(SO4)3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr and K: H: | 2 c_1 + 2 c_2 = 2 c_4 O: | 4 c_1 + 7 c_3 = c_4 + 4 c_5 + 12 c_7 S: | c_1 + c_2 = c_5 + c_6 + 3 c_7 Cr: | 2 c_3 = c_7 K: | 2 c_3 = 2 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_2 = 3 c_1 - 21 c_3 = 1 c_4 = 4 c_1 - 21 c_5 = 1 c_6 = 4 c_1 - 28 c_7 = 2 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 8 and solve for the remaining coefficients: c_1 = 8 c_2 = 3 c_3 = 1 c_4 = 11 c_5 = 1 c_6 = 4 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 8 + 3 + ⟶ 11 + + 4 + 2 Cr(SO4)3
Balance the chemical equation algebraically: + + ⟶ + + + Cr(SO4)3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Cr(SO4)3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr and K: H: | 2 c_1 + 2 c_2 = 2 c_4 O: | 4 c_1 + 7 c_3 = c_4 + 4 c_5 + 12 c_7 S: | c_1 + c_2 = c_5 + c_6 + 3 c_7 Cr: | 2 c_3 = c_7 K: | 2 c_3 = 2 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_2 = 3 c_1 - 21 c_3 = 1 c_4 = 4 c_1 - 21 c_5 = 1 c_6 = 4 c_1 - 28 c_7 = 2 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 8 and solve for the remaining coefficients: c_1 = 8 c_2 = 3 c_3 = 1 c_4 = 11 c_5 = 1 c_6 = 4 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 3 + ⟶ 11 + + 4 + 2 Cr(SO4)3

Structures

 + + ⟶ + + + Cr(SO4)3
+ + ⟶ + + + Cr(SO4)3

Names

sulfuric acid + hydrogen sulfide + potassium dichromate ⟶ water + potassium sulfate + mixed sulfur + Cr(SO4)3
sulfuric acid + hydrogen sulfide + potassium dichromate ⟶ water + potassium sulfate + mixed sulfur + Cr(SO4)3

Chemical names and formulas

 | sulfuric acid | hydrogen sulfide | potassium dichromate | water | potassium sulfate | mixed sulfur | Cr(SO4)3 formula | | | | | | | Cr(SO4)3 Hill formula | H_2O_4S | H_2S | Cr_2K_2O_7 | H_2O | K_2O_4S | S | CrO12S3 name | sulfuric acid | hydrogen sulfide | potassium dichromate | water | potassium sulfate | mixed sulfur |  IUPAC name | sulfuric acid | hydrogen sulfide | dipotassium oxido-(oxido-dioxochromio)oxy-dioxochromium | water | dipotassium sulfate | sulfur |
| sulfuric acid | hydrogen sulfide | potassium dichromate | water | potassium sulfate | mixed sulfur | Cr(SO4)3 formula | | | | | | | Cr(SO4)3 Hill formula | H_2O_4S | H_2S | Cr_2K_2O_7 | H_2O | K_2O_4S | S | CrO12S3 name | sulfuric acid | hydrogen sulfide | potassium dichromate | water | potassium sulfate | mixed sulfur | IUPAC name | sulfuric acid | hydrogen sulfide | dipotassium oxido-(oxido-dioxochromio)oxy-dioxochromium | water | dipotassium sulfate | sulfur |