Input interpretation
![2, 2-bis(4-hydroxyphenyl)hexafluoropropane | molar mass](../image_source/97f1abeb6bedf0dfbed99439861f0bd7.png)
2, 2-bis(4-hydroxyphenyl)hexafluoropropane | molar mass
Result
![Find the molar mass, M, for 2, 2-bis(4-hydroxyphenyl)hexafluoropropane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_15H_10F_6O_2 Use the chemical formula, C_15H_10F_6O_2, to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 2 C (carbon) | 15 F (fluorine) | 6 H (hydrogen) | 10 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 2 | 15.999 C (carbon) | 15 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 10 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 C (carbon) | 15 | 12.011 | 15 × 12.011 = 180.165 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 M = 31.998 g/mol + 180.165 g/mol + 113.990418978 g/mol + 10.080 g/mol = 336.233 g/mol](../image_source/ec4ed9899dbb272fcd013f1e2e42a723.png)
Find the molar mass, M, for 2, 2-bis(4-hydroxyphenyl)hexafluoropropane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_15H_10F_6O_2 Use the chemical formula, C_15H_10F_6O_2, to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 2 C (carbon) | 15 F (fluorine) | 6 H (hydrogen) | 10 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 2 | 15.999 C (carbon) | 15 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 10 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 C (carbon) | 15 | 12.011 | 15 × 12.011 = 180.165 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 M = 31.998 g/mol + 180.165 g/mol + 113.990418978 g/mol + 10.080 g/mol = 336.233 g/mol
Unit conversion
![0.3362 kg/mol (kilograms per mole)](../image_source/37a8ad76b297024f97b32cf877aa646f.png)
0.3362 kg/mol (kilograms per mole)
Comparisons
![≈ 0.47 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/ab3bfd6e6e89d8010bca89348d87a843.png)
≈ 0.47 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/2b93debd641dc4b8f3c5dc0444eac00f.png)
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/43bb3db038be269d6c2a64e10d7cb3aa.png)
≈ 5.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.6×10^-22 grams | 5.6×10^-25 kg (kilograms) | 336 u (unified atomic mass units) | 336 Da (daltons)](../image_source/b745306d92d640eb3e3693d6520a7dc9.png)
Mass of a molecule m from m = M/N_A: | 5.6×10^-22 grams | 5.6×10^-25 kg (kilograms) | 336 u (unified atomic mass units) | 336 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 336](../image_source/6aeac74f48b37344ec6f943dba90297e.png)
Relative molecular mass M_r from M_r = M_u/M: | 336