Input interpretation
![trans-10, 11-dibromodibenzosuberone | molar mass](../image_source/785580c95fa6ef048d9cddba672a013c.png)
trans-10, 11-dibromodibenzosuberone | molar mass
Result
![Find the molar mass, M, for trans-10, 11-dibromodibenzosuberone: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_15H_10Br_2O Use the chemical formula, C_15H_10Br_2O, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 2 C (carbon) | 15 H (hydrogen) | 10 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 2 | 79.904 C (carbon) | 15 | 12.011 H (hydrogen) | 10 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 2 | 79.904 | 2 × 79.904 = 159.808 C (carbon) | 15 | 12.011 | 15 × 12.011 = 180.165 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 159.808 g/mol + 180.165 g/mol + 10.080 g/mol + 15.999 g/mol = 366.052 g/mol](../image_source/6ace5d0c926feac3360139df9130a13a.png)
Find the molar mass, M, for trans-10, 11-dibromodibenzosuberone: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_15H_10Br_2O Use the chemical formula, C_15H_10Br_2O, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 2 C (carbon) | 15 H (hydrogen) | 10 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 2 | 79.904 C (carbon) | 15 | 12.011 H (hydrogen) | 10 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 2 | 79.904 | 2 × 79.904 = 159.808 C (carbon) | 15 | 12.011 | 15 × 12.011 = 180.165 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 159.808 g/mol + 180.165 g/mol + 10.080 g/mol + 15.999 g/mol = 366.052 g/mol
Unit conversion
![0.36605 kg/mol (kilograms per mole)](../image_source/2fb2e72993d500520f0f3f4d5aa2099a.png)
0.36605 kg/mol (kilograms per mole)
Comparisons
![≈ 0.51 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/f49e0fcac4421bdd7bb6b253b81e4764.png)
≈ 0.51 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/3551a43fabf0bc6b3d005e72786cc9f2.png)
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/7a543d19d6775c0b236a265cdf1fbb04.png)
≈ 6.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.1×10^-22 grams | 6.1×10^-25 kg (kilograms) | 366 u (unified atomic mass units) | 366 Da (daltons)](../image_source/69ab4532e453b9f1243a25cab09874a4.png)
Mass of a molecule m from m = M/N_A: | 6.1×10^-22 grams | 6.1×10^-25 kg (kilograms) | 366 u (unified atomic mass units) | 366 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 366](../image_source/2cf38b926f90ec2b3d746c1c5c47827e.png)
Relative molecular mass M_r from M_r = M_u/M: | 366