Input interpretation
nitroprusside | molar mass
Result
Find the molar mass, M, for nitroprusside: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_5FeN_6O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 5 Fe (iron) | 1 N (nitrogen) | 6 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 5 | 12.011 Fe (iron) | 1 | 55.845 N (nitrogen) | 6 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 Fe (iron) | 1 | 55.845 | 1 × 55.845 = 55.845 N (nitrogen) | 6 | 14.007 | 6 × 14.007 = 84.042 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 60.055 g/mol + 55.845 g/mol + 84.042 g/mol + 15.999 g/mol = 215.941 g/mol
Unit conversion
0.21594 kg/mol (kilograms per mole)
Comparisons
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 216 u (unified atomic mass units) | 216 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 216