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mass fractions of copper iron oxide

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copper iron oxide | elemental composition
copper iron oxide | elemental composition

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Find the elemental composition for copper iron oxide in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: CuFe_2O_4 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule:  | number of atoms  Cu (copper) | 1  Fe (iron) | 2  O (oxygen) | 4  N_atoms = 1 + 2 + 4 = 7 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work:  | number of atoms | atom fraction  Cu (copper) | 1 | 1/7  Fe (iron) | 2 | 2/7  O (oxygen) | 4 | 4/7 Check: 1/7 + 2/7 + 4/7 = 1 Compute atom percents using the atom fractions:  | number of atoms | atom percent  Cu (copper) | 1 | 1/7 × 100% = 14.3%  Fe (iron) | 2 | 2/7 × 100% = 28.6%  O (oxygen) | 4 | 4/7 × 100% = 57.1% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | number of atoms | atom percent | atomic mass/u  Cu (copper) | 1 | 14.3% | 63.546  Fe (iron) | 2 | 28.6% | 55.845  O (oxygen) | 4 | 57.1% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m:  | number of atoms | atom percent | atomic mass/u | mass/u  Cu (copper) | 1 | 14.3% | 63.546 | 1 × 63.546 = 63.546  Fe (iron) | 2 | 28.6% | 55.845 | 2 × 55.845 = 111.690  O (oxygen) | 4 | 57.1% | 15.999 | 4 × 15.999 = 63.996  m = 63.546 u + 111.690 u + 63.996 u = 239.232 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work:  | number of atoms | atom percent | mass fraction  Cu (copper) | 1 | 14.3% | 63.546/239.232  Fe (iron) | 2 | 28.6% | 111.690/239.232  O (oxygen) | 4 | 57.1% | 63.996/239.232 Check: 63.546/239.232 + 111.690/239.232 + 63.996/239.232 = 1 Compute mass percents using the mass fractions: Answer: |   | | number of atoms | atom percent | mass percent  Cu (copper) | 1 | 14.3% | 63.546/239.232 × 100% = 26.56%  Fe (iron) | 2 | 28.6% | 111.690/239.232 × 100% = 46.69%  O (oxygen) | 4 | 57.1% | 63.996/239.232 × 100% = 26.75%
Find the elemental composition for copper iron oxide in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: CuFe_2O_4 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms Cu (copper) | 1 Fe (iron) | 2 O (oxygen) | 4 N_atoms = 1 + 2 + 4 = 7 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction Cu (copper) | 1 | 1/7 Fe (iron) | 2 | 2/7 O (oxygen) | 4 | 4/7 Check: 1/7 + 2/7 + 4/7 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent Cu (copper) | 1 | 1/7 × 100% = 14.3% Fe (iron) | 2 | 2/7 × 100% = 28.6% O (oxygen) | 4 | 4/7 × 100% = 57.1% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u Cu (copper) | 1 | 14.3% | 63.546 Fe (iron) | 2 | 28.6% | 55.845 O (oxygen) | 4 | 57.1% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u Cu (copper) | 1 | 14.3% | 63.546 | 1 × 63.546 = 63.546 Fe (iron) | 2 | 28.6% | 55.845 | 2 × 55.845 = 111.690 O (oxygen) | 4 | 57.1% | 15.999 | 4 × 15.999 = 63.996 m = 63.546 u + 111.690 u + 63.996 u = 239.232 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction Cu (copper) | 1 | 14.3% | 63.546/239.232 Fe (iron) | 2 | 28.6% | 111.690/239.232 O (oxygen) | 4 | 57.1% | 63.996/239.232 Check: 63.546/239.232 + 111.690/239.232 + 63.996/239.232 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent Cu (copper) | 1 | 14.3% | 63.546/239.232 × 100% = 26.56% Fe (iron) | 2 | 28.6% | 111.690/239.232 × 100% = 46.69% O (oxygen) | 4 | 57.1% | 63.996/239.232 × 100% = 26.75%

Mass fraction pie chart

Mass fraction pie chart
Mass fraction pie chart