Input interpretation
![benzyltriphenylphosphonium chloride | molar mass](../image_source/a04129c9076b9c697beddf9819ec28e4.png)
benzyltriphenylphosphonium chloride | molar mass
Result
![Find the molar mass, M, for benzyltriphenylphosphonium chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CH_2P(Cl)(C_6H_5)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 25 Cl (chlorine) | 1 H (hydrogen) | 22 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 25 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 22 | 1.008 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 25 | 12.011 | 25 × 12.011 = 300.275 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 22 | 1.008 | 22 × 1.008 = 22.176 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 300.275 g/mol + 35.45 g/mol + 22.176 g/mol + 30.973761998 g/mol = 388.87 g/mol](../image_source/e4ed53e1ecae76409c8310faa52c6a63.png)
Find the molar mass, M, for benzyltriphenylphosphonium chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CH_2P(Cl)(C_6H_5)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 25 Cl (chlorine) | 1 H (hydrogen) | 22 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 25 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 22 | 1.008 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 25 | 12.011 | 25 × 12.011 = 300.275 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 22 | 1.008 | 22 × 1.008 = 22.176 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 300.275 g/mol + 35.45 g/mol + 22.176 g/mol + 30.973761998 g/mol = 388.87 g/mol
Unit conversion
![0.38887 kg/mol (kilograms per mole)](../image_source/7fd602f201b02f80d6f8db45515d1b44.png)
0.38887 kg/mol (kilograms per mole)
Comparisons
![≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/ae0f36084426493a40dfbdf8a16e384d.png)
≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/364effc72d5c32b38de907d961693150.png)
≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/2f271b4a94da3c63400f402ab1ecdd2a.png)
≈ 6.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.5×10^-22 grams | 6.5×10^-25 kg (kilograms) | 389 u (unified atomic mass units) | 389 Da (daltons)](../image_source/cc19f9ddea7c7371311d29715545f444.png)
Mass of a molecule m from m = M/N_A: | 6.5×10^-22 grams | 6.5×10^-25 kg (kilograms) | 389 u (unified atomic mass units) | 389 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 389](../image_source/8caff9c9fd4d60ee6f95eda8b20263ce.png)
Relative molecular mass M_r from M_r = M_u/M: | 389