Input interpretation
![acetaminophen | molecular mass](../image_source/609c488efa1549acb565b65e1b82ba9e.png)
acetaminophen | molecular mass
Result
![Find the molecular mass, m, for acetaminophen: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CONHC_6H_4OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 H (hydrogen) | 9 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 8 | 12.011 H (hydrogen) | 9 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 m = 96.088 u + 9.072 u + 14.007 u + 31.998 u = 151.165 u](../image_source/bdc9bb2e2884a6bf234c166e19013509.png)
Find the molecular mass, m, for acetaminophen: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CONHC_6H_4OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 H (hydrogen) | 9 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 8 | 12.011 H (hydrogen) | 9 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 m = 96.088 u + 9.072 u + 14.007 u + 31.998 u = 151.165 u
Unit conversions
![151.16 Da (daltons)](../image_source/8cb5178c3ca2ae431a70afb48ba1ca9b.png)
151.16 Da (daltons)
![0.15116 kDa (kilodaltons)](../image_source/1866ab7f2a21927de2982948b98b3850.png)
0.15116 kDa (kilodaltons)
![2.5102×10^-22 grams](../image_source/f4dee9d3036aabe22b8a3a310c03f942.png)
2.5102×10^-22 grams
![2.5102×10^-25 kg (kilograms)](../image_source/3a2c76e8df7197e44355e601ab8d0ceb.png)
2.5102×10^-25 kg (kilograms)
![151.17 chemical atomic mass units (unit officially deprecated)](../image_source/54ecba649471a7a7d8723b3d94ae7b5d.png)
151.17 chemical atomic mass units (unit officially deprecated)
![151.21 physical atomic mass units (unit officially deprecated)](../image_source/8344eab926afd8c3bb399f1e52ed1d3e.png)
151.21 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
![≈ ( 0.21 ≈ 1/5 ) × molecular mass of fullerene ( ≈ 721 u )](../image_source/534bbd93cb0df92c885c6b0331cc35a5.png)
≈ ( 0.21 ≈ 1/5 ) × molecular mass of fullerene ( ≈ 721 u )
![≈ 0.78 × molecular mass of caffeine ( ≈ 194 u )](../image_source/1a99cd8fc0adb87443ac4cceceae631e.png)
≈ 0.78 × molecular mass of caffeine ( ≈ 194 u )
![≈ 2.6 × molecular mass of sodium chloride ( ≈ 58 u )](../image_source/b189837fc8e312c2754e9ea0351c9f3a.png)
≈ 2.6 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
![Relative atomic mass A_r from A_r = m_aN_A/M_u: | 151](../image_source/6f928ddff59aafd563b316dbcff0e8f7.png)
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 151
![Molar mass M from M = m_aN_A: | 151 g/mol (grams per mole)](../image_source/1d5986773722d6b7a2fc2418b327324b.png)
Molar mass M from M = m_aN_A: | 151 g/mol (grams per mole)
![Relative molecular mass M_r from M_r = m_mN_A/M_u: | 151](../image_source/367028be6181b8cd7a79b9e4d0ed12f4.png)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 151
![Molar mass M from M = m_mN_A: | 151 g/mol (grams per mole)](../image_source/570262c952370573c3ebf4952db9320e.png)
Molar mass M from M = m_mN_A: | 151 g/mol (grams per mole)