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molar mass of fluorosilicic acid

Input interpretation

fluorosilicic acid | molar mass
fluorosilicic acid | molar mass

Result

Find the molar mass, M, for fluorosilicic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2SiF_6 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  F (fluorine) | 6  H (hydrogen) | 2  Si (silicon) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  F (fluorine) | 6 | 18.998403163  H (hydrogen) | 2 | 1.008  Si (silicon) | 1 | 28.085 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978  H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016  Si (silicon) | 1 | 28.085 | 1 × 28.085 = 28.085  M = 113.990418978 g/mol + 2.016 g/mol + 28.085 g/mol = 144.091 g/mol
Find the molar mass, M, for fluorosilicic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2SiF_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 6 H (hydrogen) | 2 Si (silicon) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 6 | 18.998403163 H (hydrogen) | 2 | 1.008 Si (silicon) | 1 | 28.085 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 Si (silicon) | 1 | 28.085 | 1 × 28.085 = 28.085 M = 113.990418978 g/mol + 2.016 g/mol + 28.085 g/mol = 144.091 g/mol

Unit conversion

0.14409 kg/mol (kilograms per mole)
0.14409 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.74 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.74 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 2.4×10^-22 grams  | 2.4×10^-25 kg (kilograms)  | 144 u (unified atomic mass units)  | 144 Da (daltons)
Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 144 u (unified atomic mass units) | 144 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 144
Relative molecular mass M_r from M_r = M_u/M: | 144