Search

H3PO4 + LiCl = HCl + Li3PO4

Input interpretation

H_3PO_4 phosphoric acid + LiCl lithium chloride ⟶ HCl hydrogen chloride + Li_3PO_4 lithium phosphate
H_3PO_4 phosphoric acid + LiCl lithium chloride ⟶ HCl hydrogen chloride + Li_3PO_4 lithium phosphate

Balanced equation

Balance the chemical equation algebraically: H_3PO_4 + LiCl ⟶ HCl + Li_3PO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_3PO_4 + c_2 LiCl ⟶ c_3 HCl + c_4 Li_3PO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, P, Cl and Li: H: | 3 c_1 = c_3 O: | 4 c_1 = 4 c_4 P: | c_1 = c_4 Cl: | c_2 = c_3 Li: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_3PO_4 + 3 LiCl ⟶ 3 HCl + Li_3PO_4
Balance the chemical equation algebraically: H_3PO_4 + LiCl ⟶ HCl + Li_3PO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_3PO_4 + c_2 LiCl ⟶ c_3 HCl + c_4 Li_3PO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, P, Cl and Li: H: | 3 c_1 = c_3 O: | 4 c_1 = 4 c_4 P: | c_1 = c_4 Cl: | c_2 = c_3 Li: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_3PO_4 + 3 LiCl ⟶ 3 HCl + Li_3PO_4

Structures

+ ⟶ +
+ ⟶ +

Names

phosphoric acid + lithium chloride ⟶ hydrogen chloride + lithium phosphate
phosphoric acid + lithium chloride ⟶ hydrogen chloride + lithium phosphate

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_3PO_4 + LiCl ⟶ HCl + Li_3PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_3PO_4 + 3 LiCl ⟶ 3 HCl + Li_3PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 1 | -1 LiCl | 3 | -3 HCl | 3 | 3 Li_3PO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_3PO_4 | 1 | -1 | ([H3PO4])^(-1) LiCl | 3 | -3 | ([LiCl])^(-3) HCl | 3 | 3 | ([HCl])^3 Li_3PO_4 | 1 | 1 | [Li3PO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H3PO4])^(-1) ([LiCl])^(-3) ([HCl])^3 [Li3PO4] = (([HCl])^3 [Li3PO4])/([H3PO4] ([LiCl])^3)
Construct the equilibrium constant, K, expression for: H_3PO_4 + LiCl ⟶ HCl + Li_3PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_3PO_4 + 3 LiCl ⟶ 3 HCl + Li_3PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 1 | -1 LiCl | 3 | -3 HCl | 3 | 3 Li_3PO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_3PO_4 | 1 | -1 | ([H3PO4])^(-1) LiCl | 3 | -3 | ([LiCl])^(-3) HCl | 3 | 3 | ([HCl])^3 Li_3PO_4 | 1 | 1 | [Li3PO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H3PO4])^(-1) ([LiCl])^(-3) ([HCl])^3 [Li3PO4] = (([HCl])^3 [Li3PO4])/([H3PO4] ([LiCl])^3)

Rate of reaction

Construct the rate of reaction expression for: H_3PO_4 + LiCl ⟶ HCl + Li_3PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_3PO_4 + 3 LiCl ⟶ 3 HCl + Li_3PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 1 | -1 LiCl | 3 | -3 HCl | 3 | 3 Li_3PO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_3PO_4 | 1 | -1 | -(Δ[H3PO4])/(Δt) LiCl | 3 | -3 | -1/3 (Δ[LiCl])/(Δt) HCl | 3 | 3 | 1/3 (Δ[HCl])/(Δt) Li_3PO_4 | 1 | 1 | (Δ[Li3PO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H3PO4])/(Δt) = -1/3 (Δ[LiCl])/(Δt) = 1/3 (Δ[HCl])/(Δt) = (Δ[Li3PO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_3PO_4 + LiCl ⟶ HCl + Li_3PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_3PO_4 + 3 LiCl ⟶ 3 HCl + Li_3PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 1 | -1 LiCl | 3 | -3 HCl | 3 | 3 Li_3PO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_3PO_4 | 1 | -1 | -(Δ[H3PO4])/(Δt) LiCl | 3 | -3 | -1/3 (Δ[LiCl])/(Δt) HCl | 3 | 3 | 1/3 (Δ[HCl])/(Δt) Li_3PO_4 | 1 | 1 | (Δ[Li3PO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H3PO4])/(Δt) = -1/3 (Δ[LiCl])/(Δt) = 1/3 (Δ[HCl])/(Δt) = (Δ[Li3PO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| phosphoric acid | lithium chloride | hydrogen chloride | lithium phosphate formula | H_3PO_4 | LiCl | HCl | Li_3PO_4 Hill formula | H_3O_4P | ClLi | ClH | Li_3O_4P name | phosphoric acid | lithium chloride | hydrogen chloride | lithium phosphate IUPAC name | phosphoric acid | lithium chloride | hydrogen chloride | trilithium phosphate
| phosphoric acid | lithium chloride | hydrogen chloride | lithium phosphate formula | H_3PO_4 | LiCl | HCl | Li_3PO_4 Hill formula | H_3O_4P | ClLi | ClH | Li_3O_4P name | phosphoric acid | lithium chloride | hydrogen chloride | lithium phosphate IUPAC name | phosphoric acid | lithium chloride | hydrogen chloride | trilithium phosphate

Substance properties

| phosphoric acid | lithium chloride | hydrogen chloride | lithium phosphate molar mass | 97.994 g/mol | 42.4 g/mol | 36.46 g/mol | 115.8 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | melting point | 42.4 °C | 605 °C | -114.17 °C | boiling point | 158 °C | 1382 °C | -85 °C | density | 1.685 g/cm^3 | 2.07 g/cm^3 | 0.00149 g/cm^3 (at 25 °C) | solubility in water | very soluble | | miscible | dynamic viscosity | | 0.00525 Pa s (at 20 °C) | | odor | odorless | | |
| phosphoric acid | lithium chloride | hydrogen chloride | lithium phosphate molar mass | 97.994 g/mol | 42.4 g/mol | 36.46 g/mol | 115.8 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | melting point | 42.4 °C | 605 °C | -114.17 °C | boiling point | 158 °C | 1382 °C | -85 °C | density | 1.685 g/cm^3 | 2.07 g/cm^3 | 0.00149 g/cm^3 (at 25 °C) | solubility in water | very soluble | | miscible | dynamic viscosity | | 0.00525 Pa s (at 20 °C) | | odor | odorless | | |

Units

Random Queries

chemical types of deuterium hydride vs erbium hydride
(melting point of lead(II) acetate trihydrate)/(decomposition point of lead(II) acetate trihydrate)
alternate names of bromocresol green
alternate names of magnesium hydroxide vs sodium hydride
final decay products of Al-40
Cu + OH = Cu(OH)2
formula of sodium bromate
aluminum vs barium vs erbium
CAS number of copper(II) sulfate,basic
SMILES identifier of chlorine pentafluoride