Input interpretation
![4-(bromomethyl)phenylboronic acid | molar mass](../image_source/dcdd3c6be4cccd895ec7c35db3e29ecf.png)
4-(bromomethyl)phenylboronic acid | molar mass
Result
![Find the molar mass, M, for 4-(bromomethyl)phenylboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrCH_2(C_6H_4)B(OH)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 Br (bromine) | 1 C (carbon) | 7 H (hydrogen) | 8 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 Br (bromine) | 1 | 79.904 C (carbon) | 7 | 12.011 H (hydrogen) | 8 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 10.81 g/mol + 79.904 g/mol + 84.077 g/mol + 8.064 g/mol + 31.998 g/mol = 214.85 g/mol](../image_source/32a3b7f8ce7d1ecc34f6d81c7ff83fe8.png)
Find the molar mass, M, for 4-(bromomethyl)phenylboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrCH_2(C_6H_4)B(OH)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 Br (bromine) | 1 C (carbon) | 7 H (hydrogen) | 8 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 Br (bromine) | 1 | 79.904 C (carbon) | 7 | 12.011 H (hydrogen) | 8 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 10.81 g/mol + 79.904 g/mol + 84.077 g/mol + 8.064 g/mol + 31.998 g/mol = 214.85 g/mol
Unit conversion
![0.21485 kg/mol (kilograms per mole)](../image_source/e71d4af2e93a42665fdefd927c135ae5.png)
0.21485 kg/mol (kilograms per mole)
Comparisons
![≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/c688a646bfa0e2a7e4465ab0b6c23ea2.png)
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/0b19750123c586e96a1a1ffb984a505e.png)
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/b80c90ce7911233bbdae81ecaf5e0c6f.png)
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 215 u (unified atomic mass units) | 215 Da (daltons)](../image_source/015dc33994153cb41033af83f0da2b2c.png)
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 215 u (unified atomic mass units) | 215 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 215](../image_source/b3b504cef9aceb13c2f7f14619a4036e.png)
Relative molecular mass M_r from M_r = M_u/M: | 215