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NaOH + Fe(NO3)2 = NaNO3 + Fe(OH)2

Input interpretation

NaOH sodium hydroxide + Fe(NO_3)_2 iron(II) nitrate ⟶ NaNO_3 sodium nitrate + Fe(OH)_2 iron(II) hydroxide
NaOH sodium hydroxide + Fe(NO_3)_2 iron(II) nitrate ⟶ NaNO_3 sodium nitrate + Fe(OH)_2 iron(II) hydroxide

Balanced equation

Balance the chemical equation algebraically: NaOH + Fe(NO_3)_2 ⟶ NaNO_3 + Fe(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 Fe(NO_3)_2 ⟶ c_3 NaNO_3 + c_4 Fe(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, Fe and N: H: | c_1 = 2 c_4 Na: | c_1 = c_3 O: | c_1 + 6 c_2 = 3 c_3 + 2 c_4 Fe: | c_2 = c_4 N: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 NaOH + Fe(NO_3)_2 ⟶ 2 NaNO_3 + Fe(OH)_2
Balance the chemical equation algebraically: NaOH + Fe(NO_3)_2 ⟶ NaNO_3 + Fe(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 Fe(NO_3)_2 ⟶ c_3 NaNO_3 + c_4 Fe(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, Fe and N: H: | c_1 = 2 c_4 Na: | c_1 = c_3 O: | c_1 + 6 c_2 = 3 c_3 + 2 c_4 Fe: | c_2 = c_4 N: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 NaOH + Fe(NO_3)_2 ⟶ 2 NaNO_3 + Fe(OH)_2

Structures

+ ⟶ +
+ ⟶ +

Names

sodium hydroxide + iron(II) nitrate ⟶ sodium nitrate + iron(II) hydroxide
sodium hydroxide + iron(II) nitrate ⟶ sodium nitrate + iron(II) hydroxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: NaOH + Fe(NO_3)_2 ⟶ NaNO_3 + Fe(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NaOH + Fe(NO_3)_2 ⟶ 2 NaNO_3 + Fe(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 Fe(NO_3)_2 | 1 | -1 NaNO_3 | 2 | 2 Fe(OH)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 2 | -2 | ([NaOH])^(-2) Fe(NO_3)_2 | 1 | -1 | ([Fe(NO3)2])^(-1) NaNO_3 | 2 | 2 | ([NaNO3])^2 Fe(OH)_2 | 1 | 1 | [Fe(OH)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-2) ([Fe(NO3)2])^(-1) ([NaNO3])^2 [Fe(OH)2] = (([NaNO3])^2 [Fe(OH)2])/(([NaOH])^2 [Fe(NO3)2])
Construct the equilibrium constant, K, expression for: NaOH + Fe(NO_3)_2 ⟶ NaNO_3 + Fe(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NaOH + Fe(NO_3)_2 ⟶ 2 NaNO_3 + Fe(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 Fe(NO_3)_2 | 1 | -1 NaNO_3 | 2 | 2 Fe(OH)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 2 | -2 | ([NaOH])^(-2) Fe(NO_3)_2 | 1 | -1 | ([Fe(NO3)2])^(-1) NaNO_3 | 2 | 2 | ([NaNO3])^2 Fe(OH)_2 | 1 | 1 | [Fe(OH)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-2) ([Fe(NO3)2])^(-1) ([NaNO3])^2 [Fe(OH)2] = (([NaNO3])^2 [Fe(OH)2])/(([NaOH])^2 [Fe(NO3)2])

Rate of reaction

Construct the rate of reaction expression for: NaOH + Fe(NO_3)_2 ⟶ NaNO_3 + Fe(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NaOH + Fe(NO_3)_2 ⟶ 2 NaNO_3 + Fe(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 Fe(NO_3)_2 | 1 | -1 NaNO_3 | 2 | 2 Fe(OH)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 2 | -2 | -1/2 (Δ[NaOH])/(Δt) Fe(NO_3)_2 | 1 | -1 | -(Δ[Fe(NO3)2])/(Δt) NaNO_3 | 2 | 2 | 1/2 (Δ[NaNO3])/(Δt) Fe(OH)_2 | 1 | 1 | (Δ[Fe(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[NaOH])/(Δt) = -(Δ[Fe(NO3)2])/(Δt) = 1/2 (Δ[NaNO3])/(Δt) = (Δ[Fe(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NaOH + Fe(NO_3)_2 ⟶ NaNO_3 + Fe(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NaOH + Fe(NO_3)_2 ⟶ 2 NaNO_3 + Fe(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 Fe(NO_3)_2 | 1 | -1 NaNO_3 | 2 | 2 Fe(OH)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 2 | -2 | -1/2 (Δ[NaOH])/(Δt) Fe(NO_3)_2 | 1 | -1 | -(Δ[Fe(NO3)2])/(Δt) NaNO_3 | 2 | 2 | 1/2 (Δ[NaNO3])/(Δt) Fe(OH)_2 | 1 | 1 | (Δ[Fe(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[NaOH])/(Δt) = -(Δ[Fe(NO3)2])/(Δt) = 1/2 (Δ[NaNO3])/(Δt) = (Δ[Fe(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| sodium hydroxide | iron(II) nitrate | sodium nitrate | iron(II) hydroxide formula | NaOH | Fe(NO_3)_2 | NaNO_3 | Fe(OH)_2 Hill formula | HNaO | FeN_2O_6 | NNaO_3 | FeH_2O_2 name | sodium hydroxide | iron(II) nitrate | sodium nitrate | iron(II) hydroxide IUPAC name | sodium hydroxide | | sodium nitrate | ferrous dihydroxide
| sodium hydroxide | iron(II) nitrate | sodium nitrate | iron(II) hydroxide formula | NaOH | Fe(NO_3)_2 | NaNO_3 | Fe(OH)_2 Hill formula | HNaO | FeN_2O_6 | NNaO_3 | FeH_2O_2 name | sodium hydroxide | iron(II) nitrate | sodium nitrate | iron(II) hydroxide IUPAC name | sodium hydroxide | | sodium nitrate | ferrous dihydroxide

Substance properties

| sodium hydroxide | iron(II) nitrate | sodium nitrate | iron(II) hydroxide molar mass | 39.997 g/mol | 179.85 g/mol | 84.994 g/mol | 89.86 g/mol phase | solid (at STP) | | solid (at STP) | melting point | 323 °C | | 306 °C | boiling point | 1390 °C | | | density | 2.13 g/cm^3 | | 2.26 g/cm^3 | solubility in water | soluble | | soluble | surface tension | 0.07435 N/m | | | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 0.003 Pa s (at 250 °C) |
| sodium hydroxide | iron(II) nitrate | sodium nitrate | iron(II) hydroxide molar mass | 39.997 g/mol | 179.85 g/mol | 84.994 g/mol | 89.86 g/mol phase | solid (at STP) | | solid (at STP) | melting point | 323 °C | | 306 °C | boiling point | 1390 °C | | | density | 2.13 g/cm^3 | | 2.26 g/cm^3 | solubility in water | soluble | | soluble | surface tension | 0.07435 N/m | | | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 0.003 Pa s (at 250 °C) |

Units

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