Input interpretation
![mechlorethamine hydrochloride | molar mass](../image_source/73b22acdd6b146307d23bfedd7c44b04.png)
mechlorethamine hydrochloride | molar mass
Result
![Find the molar mass, M, for mechlorethamine hydrochloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (ClCH_2CH_2)_2NCH_3·HCl Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 5 Cl (chlorine) | 3 H (hydrogen) | 12 N (nitrogen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 5 | 12.011 Cl (chlorine) | 3 | 35.45 H (hydrogen) | 12 | 1.008 N (nitrogen) | 1 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 M = 60.055 g/mol + 106.35 g/mol + 12.096 g/mol + 14.007 g/mol = 192.51 g/mol](../image_source/9f8bfacda7eaf9569d7e14d910c28f82.png)
Find the molar mass, M, for mechlorethamine hydrochloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (ClCH_2CH_2)_2NCH_3·HCl Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 5 Cl (chlorine) | 3 H (hydrogen) | 12 N (nitrogen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 5 | 12.011 Cl (chlorine) | 3 | 35.45 H (hydrogen) | 12 | 1.008 N (nitrogen) | 1 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 M = 60.055 g/mol + 106.35 g/mol + 12.096 g/mol + 14.007 g/mol = 192.51 g/mol
Unit conversion
![0.1925 kg/mol (kilograms per mole)](../image_source/fe6441cb506529143d59acdb5a1c9f6a.png)
0.1925 kg/mol (kilograms per mole)
Comparisons
![≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/65d153ad3313dda6f2ff813dd316a8ca.png)
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.991 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/7ebc38bfe3c90de6ca00b9fd25d78310.png)
≈ 0.991 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/9b2c0e41bfee91a41824d48f62dd677d.png)
≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 193 u (unified atomic mass units) | 193 Da (daltons)](../image_source/c80ecad3f02877394b89c9ceddd61a75.png)
Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 193 u (unified atomic mass units) | 193 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 193](../image_source/ef3ce484f74ee8c472a41299c203abc1.png)
Relative molecular mass M_r from M_r = M_u/M: | 193