Input interpretation
deuterium iodide
Chemical names and formulas
formula | DI Hill formula | (1H)I name | deuterium iodide mass fractions | I (iodine) 0.992% | H (hydrogen) 0.00788%
Lewis structure
Draw the Lewis structure of deuterium iodide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the hydrogen (n_H, val = 1) and iodine (n_I, val = 7) atoms: n_H, val + n_I, val = 8 Calculate the number of electrons needed to completely fill the valence shells for hydrogen (n_H, full = 2) and iodine (n_I, full = 8): n_H, full + n_I, full = 10 Subtracting these two numbers shows that 10 - 8 = 2 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There is 1 bond and hence 2 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 8 - 2 = 6 electrons left to draw: Answer: | |
3D structure
3D structure
Basic properties
molar mass | 127.9123 g/mol phase | gas (at STP) boiling point | -35.1 °C
Units
Non-standard atom properties
H-1 | 1
Chemical identifiers
CAS number | 14104-45-1 PubChem CID number | 123337 SMILES identifier | I InChI identifier | InChI=1/HI/h1H/i/hH/f/i1H