HBO2 = H2O + H2B4O7

metaboric acid ⟶ water + H2B4O7

Balance the chemical equation algebraically: ⟶ + H2B4O7 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 ⟶ c_2 + c_3 H2B4O7 Set the number of atoms in the reactants equal to the number of atoms in the products for B, H and O: B: | c_1 = 4 c_3 H: | c_1 = 2 c_2 + 2 c_3 O: | 2 c_1 = c_2 + 7 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 ⟶ + H2B4O7

⟶ + H2B4O7

metaboric acid ⟶ water + H2B4O7

| metaboric acid | water | H2B4O7 formula | | | H2B4O7 Hill formula | BHO_2 | H_2O | H2B4O7 name | metaboric acid | water | IUPAC name | oxoborinic acid | water |

| metaboric acid | water | H2B4O7 molar mass | 43.82 g/mol | 18.015 g/mol | 157.2 g/mol phase | | liquid (at STP) | melting point | | 0 °C | boiling point | | 99.9839 °C | density | 2.49 g/cm^3 | 1 g/cm^3 | surface tension | | 0.0728 N/m | dynamic viscosity | | 8.9×10^-4 Pa s (at 25 °C) | odor | | odorless |