Input interpretation
![2, 3, 4-trifluorobenzaldehyde | molar mass](../image_source/1343c14a07c5a44ce6eefe0cbc7361b3.png)
2, 3, 4-trifluorobenzaldehyde | molar mass
Result
![Find the molar mass, M, for 2, 3, 4-trifluorobenzaldehyde: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: F_3C_6H_2CHO Use the chemical formula, F_3C_6H_2CHO, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 F (fluorine) | 3 H (hydrogen) | 3 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 3 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 84.077 g/mol + 56.995209489 g/mol + 3.024 g/mol + 15.999 g/mol = 160.095 g/mol](../image_source/1bce1701b22af75f29ff29393338b444.png)
Find the molar mass, M, for 2, 3, 4-trifluorobenzaldehyde: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: F_3C_6H_2CHO Use the chemical formula, F_3C_6H_2CHO, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 F (fluorine) | 3 H (hydrogen) | 3 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 3 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 84.077 g/mol + 56.995209489 g/mol + 3.024 g/mol + 15.999 g/mol = 160.095 g/mol
Unit conversion
![0.1601 kg/mol (kilograms per mole)](../image_source/cf1f7d1e133a0adaf1306e908a75106b.png)
0.1601 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.22 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/acdf978399a69f1f28a8d9370930ace5.png)
≈ ( 0.22 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.82 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/01e2996b074a20410b9312267e306e24.png)
≈ 0.82 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/94939188b99e2eb92feb0c14d5c6a4c8.png)
≈ 2.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 160 u (unified atomic mass units) | 160 Da (daltons)](../image_source/d83ed24170dda4c2b6b5562a0feed19c.png)
Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 160 u (unified atomic mass units) | 160 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 160](../image_source/c2708485e1e9e99e7dbfd594ea86d6de.png)
Relative molecular mass M_r from M_r = M_u/M: | 160