Input interpretation
cerium(III) sulfide | molar mass
Result
Find the molar mass, M, for cerium(III) sulfide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ce_2S_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ce (cerium) | 2 S (sulfur) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ce (cerium) | 2 | 140.116 S (sulfur) | 3 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ce (cerium) | 2 | 140.116 | 2 × 140.116 = 280.232 S (sulfur) | 3 | 32.06 | 3 × 32.06 = 96.18 M = 280.232 g/mol + 96.18 g/mol = 376.41 g/mol
Unit conversion
0.37641 kg/mol (kilograms per mole)
Comparisons
≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 6.3×10^-22 grams | 6.3×10^-25 kg (kilograms) | 376 u (unified atomic mass units) | 376 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 376