Input interpretation
cesium orthovanadate | molecular mass
Result
Find the molecular mass, m, for cesium orthovanadate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cs_3VO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cs (cesium) | 3 O (oxygen) | 4 V (vanadium) | 1 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u Cs (cesium) | 3 | 132.90545196 O (oxygen) | 4 | 15.999 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u Cs (cesium) | 3 | 132.90545196 | 3 × 132.90545196 = 398.71635588 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 m = 398.71635588 u + 63.996 u + 50.9415 u = 513.654 u
Unit conversions
513.654 Da (daltons)
0.513654 kDa (kilodaltons)
8.5294×10^-22 grams
8.5294×10^-25 kg (kilograms)
513.676 chemical atomic mass units (unit officially deprecated)
513.817 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
≈ 0.71 × molecular mass of fullerene ( ≈ 721 u )
≈ 2.6 × molecular mass of caffeine ( ≈ 194 u )
≈ 8.8 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 514
Molar mass M from M = m_aN_A: | 514 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 514
Molar mass M from M = m_mN_A: | 514 g/mol (grams per mole)