Input interpretation
![10, 16-dihydroxypalmitate | molar mass](../image_source/df1193b4542ed0020c5df9ebfa71b307.png)
10, 16-dihydroxypalmitate | molar mass
Result
![Find the molar mass, M, for 10, 16-dihydroxypalmitate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_16H_32O_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 16 H (hydrogen) | 31 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 16 | 12.011 H (hydrogen) | 31 | 1.008 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 16 | 12.011 | 16 × 12.011 = 192.176 H (hydrogen) | 31 | 1.008 | 31 × 1.008 = 31.248 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 192.176 g/mol + 31.248 g/mol + 63.996 g/mol = 287.420 g/mol](../image_source/0907e7c7037bb03da1524e631c709b43.png)
Find the molar mass, M, for 10, 16-dihydroxypalmitate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_16H_32O_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 16 H (hydrogen) | 31 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 16 | 12.011 H (hydrogen) | 31 | 1.008 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 16 | 12.011 | 16 × 12.011 = 192.176 H (hydrogen) | 31 | 1.008 | 31 × 1.008 = 31.248 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 192.176 g/mol + 31.248 g/mol + 63.996 g/mol = 287.420 g/mol
Unit conversion
![0.28742 kg/mol (kilograms per mole)](../image_source/a3e22dae58f48c7d9b8dcf541ca7e4f1.png)
0.28742 kg/mol (kilograms per mole)
Comparisons
![≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/49491b0e52ab2ba440a03ab799944092.png)
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/99729ed7620d0b0ac20b87991ad8fc09.png)
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/7f6a0fd215d458fefd8c1961b28b7196.png)
≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 287 u (unified atomic mass units) | 287 Da (daltons)](../image_source/bd9e3dad6891ca18e472ad41904e3c1d.png)
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 287 u (unified atomic mass units) | 287 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 287](../image_source/fd5d188eb7fdbd910ac79ef06ff3f48d.png)
Relative molecular mass M_r from M_r = M_u/M: | 287