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molar mass of 2-bromobutyric acid

Input interpretation

2-bromobutyric acid | molar mass
2-bromobutyric acid | molar mass

Result

Find the molar mass, M, for 2-bromobutyric acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_2H_5CH(Br)CO_2H Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Br (bromine) | 1  C (carbon) | 4  H (hydrogen) | 7  O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Br (bromine) | 1 | 79.904  C (carbon) | 4 | 12.011  H (hydrogen) | 7 | 1.008  O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904  C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044  H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  M = 79.904 g/mol + 48.044 g/mol + 7.056 g/mol + 31.998 g/mol = 167.002 g/mol
Find the molar mass, M, for 2-bromobutyric acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_2H_5CH(Br)CO_2H Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 4 H (hydrogen) | 7 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 4 | 12.011 H (hydrogen) | 7 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 79.904 g/mol + 48.044 g/mol + 7.056 g/mol + 31.998 g/mol = 167.002 g/mol

Unit conversion

0.167 kg/mol (kilograms per mole)
0.167 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.86 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.86 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 2.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 2.9 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 2.8×10^-22 grams  | 2.8×10^-25 kg (kilograms)  | 167 u (unified atomic mass units)  | 167 Da (daltons)
Mass of a molecule m from m = M/N_A: | 2.8×10^-22 grams | 2.8×10^-25 kg (kilograms) | 167 u (unified atomic mass units) | 167 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 167
Relative molecular mass M_r from M_r = M_u/M: | 167