Input interpretation
water + bromine + nitrous acid ⟶ nitric acid + hydrogen bromide
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Br and N: H: | 2 c_1 + c_3 = c_4 + c_5 O: | c_1 + 2 c_3 = 3 c_4 Br: | 2 c_2 = c_5 N: | c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | + + ⟶ + 2
Structures
+ + ⟶ +
Names
water + bromine + nitrous acid ⟶ nitric acid + hydrogen bromide
Chemical names and formulas
| water | bromine | nitrous acid | nitric acid | hydrogen bromide Hill formula | H_2O | Br_2 | HNO_2 | HNO_3 | BrH name | water | bromine | nitrous acid | nitric acid | hydrogen bromide IUPAC name | water | molecular bromine | nitrous acid | nitric acid | hydrogen bromide