Input interpretation
![zirconium(IV) carbonate hydroxide oxide | molar mass](../image_source/ca7aa064670feeff18f524dfec634b57.png)
zirconium(IV) carbonate hydroxide oxide | molar mass
Result
![Find the molar mass, M, for zirconium(IV) carbonate hydroxide oxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Zr(OH)_2CO_3·ZrO_2 Use the chemical formula, Zr(OH)_2CO_3·ZrO_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 H (hydrogen) | 4 O (oxygen) | 7 Zr (zirconium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 H (hydrogen) | 4 | 1.008 O (oxygen) | 7 | 15.999 Zr (zirconium) | 2 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 Zr (zirconium) | 2 | 91.224 | 2 × 91.224 = 182.448 M = 12.011 g/mol + 4.032 g/mol + 111.993 g/mol + 182.448 g/mol = 310.484 g/mol](../image_source/dd51d7174b5cc245bdf2e81c45154f8a.png)
Find the molar mass, M, for zirconium(IV) carbonate hydroxide oxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Zr(OH)_2CO_3·ZrO_2 Use the chemical formula, Zr(OH)_2CO_3·ZrO_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 H (hydrogen) | 4 O (oxygen) | 7 Zr (zirconium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 H (hydrogen) | 4 | 1.008 O (oxygen) | 7 | 15.999 Zr (zirconium) | 2 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 Zr (zirconium) | 2 | 91.224 | 2 × 91.224 = 182.448 M = 12.011 g/mol + 4.032 g/mol + 111.993 g/mol + 182.448 g/mol = 310.484 g/mol
Unit conversion
![0.31048 kg/mol (kilograms per mole)](../image_source/eeb84cbda921e9c0aea183dd1a6323e5.png)
0.31048 kg/mol (kilograms per mole)
Comparisons
![≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/dc008526a26944e2ae6ca1cac2ab23e5.png)
≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/69cf776690e15dc775c485371b1d7fac.png)
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/b8bc2f1873b87d74e40ef45294755637.png)
≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.2×10^-22 grams | 5.2×10^-25 kg (kilograms) | 310 u (unified atomic mass units) | 310 Da (daltons)](../image_source/095da63e01fcb505637bf505152d2a3a.png)
Mass of a molecule m from m = M/N_A: | 5.2×10^-22 grams | 5.2×10^-25 kg (kilograms) | 310 u (unified atomic mass units) | 310 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 310](../image_source/ca9dbb454be976944f4a61b0b746e87d.png)
Relative molecular mass M_r from M_r = M_u/M: | 310